{{fa>pencil?32}} {{elektrotechnik_1:schaltung_klws2020_2_2_2.jpg?400}} Given is the adjoining circuit with \\ $R_1=10 ~\Omega$\\ $R_2=20 ~\Omega$\\ $R_3=5 ~\Omega$\\ 1. Determine the equivalent resistance $R_{\rm eq}$ between A and B by summing the resistances. {{icon>eye}} Final result \begin{align*} R_{ges} &= \frac{20 ~\Omega \cdot 5 ~\Omega}{\frac{3}{2}\cdot 20 ~\Omega + 5 ~\Omega} = 2.858 ~\Omega \rightarrow 2.9 ~\Omega \end{align*} \\ 2. Now let the voltage from A to B be: $U_{\rm AB}=U_0= 10 ~\rm V$. What is the current $I$? {{icon>eye}} Final result \begin{align*} I =\frac{10~\rm V}{2 \cdot 5 ~\Omega} = 1 ~\rm A \end{align*} \\