{{tag>magnetic_voltage exam_ee2_SS2021}}{{include_n>1210}}
 
#@TaskTitle_HTML@##@Lvl_HTML@#~~#@ee1_taskctr#~~ Magnetic Voltage \\
<fs medium>(written test, approx. 6 % of a 120-minute written test, SS2021)</fs> #@TaskText_HTML@#

The following images show cross-sections of electrical cables. \\
A closed path is shown as a dashed line. The magnetic voltage $\theta$ on these paths shall be analyzed. \\
The following values are given for the currents: 
  * $I_1 = 5 {~\rm A}$
  * $I_2 = 2 {~\rm A}$
  * $I_3 = 1 {~\rm A}$
  * $I_4 = 4 {~\rm A}$

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Specify which magnetic voltages $\theta_{(1)}$, $\theta_{(2)}$, and $\theta_{(3)}$ result. \\
Note the direction of the path in each case! 

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For the resulting current the direction of the path has to be considered with the right-hand rule:
  * $I_{(1)} = +I_2 - I_1 - I_3 \quad \rightarrow \quad \theta_{(1)} = 2 {~\rm A} - 5 {~\rm A} - 1 {~\rm A} $ 
  * $I_{(2)} = +I_3 + I_4 - I_1 \quad \rightarrow \quad \theta_{(2)} = 1 {~\rm A} + 4 {~\rm A} - 5 {~\rm A} $  
  * $I_{(3)} = +I_3 - I_4 - I_2 \quad \rightarrow \quad \theta_{(3)} = 1 {~\rm A} - 4 {~\rm A} - 2 {~\rm A} $ 
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#@HiddenBegin_HTML~jfZlmSUcgHSQVop5_12,Result~@#
\begin{align*}
\theta_{(1)} &= -4 {~\rm A} \\
\theta_{(2)} &= 0 {~\rm A} \\
\theta_{(3)} &= -5 {~\rm A} \\
\end{align*}

#@HiddenEnd_HTML~jfZlmSUcgHSQVop5_12,Result~@#

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