==== Inverting Operational Amplifier ==== == Gain of Op-Amp == Build the following circuit in with the power supply and a multimeter. {{drawio>lab05:Fig-20_inverting_op-amp.svg}} \\ \\ \\ $U_{\rm DD}{\rm~=10~V},~U_{\rm SS}{\rm~=-10~V},~R_{\rm 1}{\rm~=10~k\Omega}$ \\ \\ Calculate the necessary value for $R_{\rm 2}$, so that the Output $U_{\rm OUT}$ is +5 V. Use the supply voltage of the operational amplifier for $U_{\rm IN}$. \\ \\ \\ $U_{\rm IN}{\rm~=}$ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ $R_{\rm 2}{\rm~=}$ \\ \\ \\ == Investigation of inverting input == \\ \\ {{drawio>lab05:Fig-30_inverting_op-amp_inv_input.svg}} \\ \\ \\ $U_{\rm DD}{\rm~=10~V},~U_{\rm SS}{\rm~=-10~V},~R_{\rm 1}{\rm~=10~k\Omega}$\\ \\ Use the values from for $U_{\rm IN},~U_{\rm OUT},~R_{\rm 2}$. \\ \\ \\ Complete the arrows in the scematic of the circuit.\\ Determine the the currents $I_{\rm 1}$ and $I_{\rm 2}$ indirectly by measuring the voltage.\\ Calculate the sum of the currents at node ${\rm N_{12}}$. \\ \\ \\ $U_{\rm 1}{\rm~=}$ \\ \\ \\ $U_{\rm 2}{\rm~=}$ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ $I_{\rm 1}{\rm~=}$ \\ \\ \\ $I_{\rm 2}{\rm~=}$ \\ \\ \\ $I_{\rm N12}{\rm~=}$ \\ \\ \\ {{drawio>lab05:Fig-40_inverting_op-amp_inv_input_virt_gnd.svg}} \\ \\ \\ \\ $U_{\rm DD}{\rm~=10~V},~U_{\rm SS}{\rm~=-10~V},~R_{\rm 1}{\rm~=10~k\Omega}$\\ \\ Use the values from for $U_{\rm IN},~U_{\rm OUT},~R_{\rm 2}$. \\ \\ \\ Complete the arrows in the scematic of the circuit.\\ Take the values for $U_{\rm 1},~U_{\rm 2},~U_{\rm OUT}$ from .\\ Use these values to calculate the sum of the voltages at node ${\rm N_{12}}$.\\ Compare your result by measuerement. \\ \\ \\ $U_{\rm 1}{\rm~=}$ \\ \\ \\ $U_{\rm 2}{\rm~=}$ \\ \\ \\ $U_{\rm OUT}{\rm~=}$ \\ \\ \\ Calculated $U_{\rm 12}{\rm~=}$ \\ \\ \\ Measured $U_{\rm 12}{\rm~=}$ \\ \\ \\ What are your results?\\ \\ ${\rm ................................................................................................}$ \\ \\ ${\rm ................................................................................................}$ \\ \\ ${\rm ................................................................................................}$ \\ \\ \\ What will happen if you short-circuit $R_{\rm 2}$?\\ Try it and explain your results.\\ \\ \\ ${\rm ................................................................................................}$ \\ \\ ${\rm ................................................................................................}$ \\ \\ ${\rm ................................................................................................}$ \\ \\ ${\rm ................................................................................................}$ \\ \\ ${\rm ................................................................................................}$ \\ \\ ${\rm ................................................................................................}$ \\ \\ ${\rm ................................................................................................}$ \\ \\ ${\rm ................................................................................................}$ \\ \\ ${\rm ................................................................................................}$ \\ \\ ${\rm ................................................................................................}$ \\ \\ ${\rm ................................................................................................}$ \\ \\