A symmetrical three-phase generator in a delta connection shall be considered in the following.
A voltage with the RMS value $U_{\rm RMS} = 110~\rm V$ is applied between the terminals of each winding.
Through each of the windings, there is a current with an RMS value $I_{\rm RMS} = 5 ~\rm A$ and a phase shift of $\varphi = +25°$ compared to the voltage.
a) Draw the circuit diagram.
b) Specify the RMS value of the phase voltage $U_\rm L$ and the string voltage $U_\rm S$.
c) Specify the RMS value of the phase current $I_\rm L$ and the string current $I_\rm S$.
d) Determine the active power.
The active power $P$ is given by: $P = 3 \cdot U \cdot I \cdot \sin(\varphi)$ \begin{align*} P &= 3 \cdot 110{~\rm V} \cdot 5{~\rm A} \cdot \sin(25°) \\ &= 1'610.888... ~\rm W \end{align*}