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--- circuit_design:1_amplifier_basics [2021/09/23 02:50]
tfischer
+++ circuit_design:1_amplifier_basics [2023/12/16 01:12] (aktuell)
mexleadmin [Bearbeiten - Panel]
@@ Zeile 1: / Zeile 1: @@
-====== 1. Amplifier Basics ======
+====== 1 Amplifier Basics ======
-===== 1.0 What is circuit design? =====
+===== 1.0 What is Circuit Design? =====
 <WRAP><panel type="default">
 <imgcaption tablelabel| Overview of the different areas of electronics></imgcaption>
-{{drawio>UebersichtElektronik}}
+{{drawio>UebersichtElektronik.svg}}
 </panel></WRAP>
 Circuit design encompasses various subfields of electronics.
-<imgref tablelabel> shows the basics of electronics, its specializations and the interfaces.
+<imgref tablelabel> shows the basics of electronics, its specializations, and the interfaces.
-\\ \\ \\
-In the subject [[Introduction to digital Systems:start]] digital technology with gates and various simple programmable circuits have already been described. In [[electrical Engineering 1:start]]  the foundations for simple electrical components and circuits were laid.
+In the subject [[Introduction to digital Systems:start]] digital technology with gates and various simple programmable circuits have already been described. In [[Electrical Engineering 1:start]]  the foundations for simple electrical components and circuits were laid.
-\\ \\ \\
 Circuit design now concentrates on __electr**on**ic components and their circuits__ that affect analog electronics.
-Die elektronische Schaltungstechnik konzentriert sich nun auf __elektr**on**ische Komponenten und deren Schaltungen__, welche die Analogelektronik betrifft.
-\\ \\ \\
-These components and circuits often connect the digital with the analog world or adjust voltages and currents for other sub-circuits. In addition, the components "transistor (TRANSfer ResISTOR)" and "diode" form the basis for both digital, power and high-frequency electronics. Without exaggerating, these components are the basis of the modern world; today they form the heart of every computer and microcontroller.
-~~PAGEBREAK~~~~CLEARFIX~~
+These components and circuits often connect the digital with the analog world or adjust voltages and currents for other sub-circuits. In addition, the components "transistor (**TRANS**fer Res**ISTOR**)" and "diode" form the basis for both digital, power, and high-frequency electronics. Without exaggerating, these components are the basis of the modern world; today they form the heart of every computer and microcontroller.
-<WRAP right noprint>
-{{youtube>hCyR7a6szFc?size=543x342}}
+=== Circuit Design and Electronics ===
-</WRAP>
-<WRAP noprint>
-\\ \\ \\
-But what distinguishes electronics from electrical engineering? And what does "(electronic) circuit design" mean? These questions should be answered in the adjacent video.
-</WRAP>
-<WRAP onlyprint>
 But what is the difference between electronics and electrical engineering? And what does electronic circuit design mean?\\
 For this purpose, it is useful to take a closer look at the individual parts of the term "electronic circuit design": \\
-The German wording for "circuit __**design**__" is "Schaltungs__**technik**__". The word "Technik" here is derived from the Greek "τέχνη" (téchne) and means as much as art or craft. At first glance, this seems a bit surprising, since "Technik" is rarely associated with an artistic activity such as painting. In the higher semesters, however, you will learn that understanding, for example, the arrangement of electronics (circuit design) and the application of the individual components requires a trained skill and creativity. This is also true for the English "design".\\ \\
+The German wording for "circuit __**design**__" is "Schaltungs__**technik**__". The word "Technik" here is derived from the Greek "τέχνη" (téchne) and means as much as art or craft. At first glance, this seems a bit surprising, since "Technik" is rarely associated with an artistic activity such as painting. In the higher semesters, however, you will learn that understanding, for example, the arrangement of electronics (circuit design) and the application of the individual components requires trained skill and creativity. This is also true for the English "design".\\ \\
-A __**circuit**__ is an arrangement of electrical or electronic components to form a functioning whole or an electric circuit. We already got to know the term circuit in [[electrical Engineering 1:start]].\\ \\
+A __**circuit**__ is an arrangement of electrical or electronic components to form a functioning whole or an electric circuit. We already got to know the term circuit in [[electrical Engineering 1:start]].\\
-__**Electronics**__ is derived from the word electrons. This "electron engineering" considers circuits in which an electric current or voltage is controlled by other electric signals. This means, for example, that a voltage $U_{in}$ controls an output voltage $U_{out}$. Physically, the two signals do not have to be electrically connected. \\ \\
+__**Electronics**__ is derived from the word electrons. This "electron engineering" considers circuits in which an electric current or voltage is controlled by other electric signals. This means, for example, that a voltage $U_{\rm in}$ controls an output voltage $U_{\rm out}$. Physically, the two signals do not have to be electrically connected. \\ \\
-First, the term electronics will be examined in more detail using various examples. First of all, a transformer will be considered. Is this an electrical or electronic component? In a transformer, the output voltage is generated by the change in the magnetic field. The magnetic field change in turn is caused by the current change on the primary side. So there is a direct transformation (a conversion) of the signals. Thus the transformer is not an electronic component. If this is still somewhat unclear, it helps to work intensively on this chapter and to compare the following examples. \\ \\
+=== Is it Electronics? Some Examples ===
-The second component to be considered is the so-called {{wp>contactor}}. A contactor is an electrically controlled switch. In this case, a coil closes a secondary, or output-side circuit if it is energized. There is no direct electrical connection here. The contactor is often not yet regarded as an electronic, but as an electromechanical component. \\ \\
-The last thing to be studied is the electron tube in the light of electronics and electrical engineering. An electron tube is a vacuum vessel, with several connections. Two of the connections lead internally to one electrode each, which face each other. These can be brought to a potential difference against each other and heated. This allows electrons to escape from the electrode and generate a current to the other electrode through the vacuum. A grid is placed between these two electrodes. If this is set to an opposite potential, the current flow can be stopped. Here, the grid potential can be used to change the current flow. The electron tube is already considered as an electronic component. Nowadays the electron tube has been replaced by semiconductor components. \\ \\
-In this course we only deal with semiconductor electronic components and basically with silicon as semiconductor.
-</WRAP>
+We will now examine the term electronics in more detail using various examples.
-~~PAGEBREAK~~~~CLEARFIX~~
+First of all, a transformer will be considered. Is this an electrical or electronic component? In a transformer, the output voltage is generated by the change in the magnetic field. The change of the magnetic field in the windings is caused by the current change on the primary side. So, there is a direct transformation (a conversion) of the signals. The transformer is not considered as an electronic component. This is due to the fact that the input signal not only provides the control but also the electric power. If this is still somewhat unclear, it helps to work intensively on this chapter and to compare the following examples.
-===== 1.1 Why amplifiers? =====
+The second example is the so-called {{wp>contactor}}. A contactor is an electrically controlled switch. In this case, a coil closes a secondary, or output-side circuit if it is energized. There is no direct electrical connection here. The contactor is often not yet regarded as an electronic but as an electromechanical component. This component is on the border between the electronic and electrical components.
-The amplifier is one - if not the - central component in electronics. To understand what it is used for, various examples are shown in the three short videos.
+The last example to be studied in the light of electronics and electrical engineering is the electron tube. An electron tube is a vacuum vessel, with several connections. Two of the connections lead internally to one electrode each, which faces each other. These can be brought to a potential difference against each other and heated. This allows electrons to escape from the electrode and generate a current to the other electrode through the vacuum. A grid is placed between these two electrodes. If this is set to an opposite potential, the current flow can be stopped. Here, the grid potential can be used to change the current flow. The electron tube is already considered an electronic component. Nowadays the electron tube has been replaced by semiconductor components. \\ \\
+In this course, we only deal with semiconductor electronic components and basically with silicon as semiconductor.
-In example 1, the amplifier is briefly explained from the point of view of acoustics.
-<WRAP noprint>
+~~PAGEBREAK~~~~CLEARFIX~~
-{{youtube>KbrHOcgmRkI?size=543x342}}
-</WRAP>
-In example 2, a sensor with variable resistance is to be evaluated. This case occurs very often with passive sensors (i.e. sensors without further signal conditioning). Many of these sensors only generate a small voltage difference or a very small current. If these sensors were connected directly to a consumer or another circuit with low input resistance, the measuring voltage would break down and the measuring signal determined from it would be falsified.
-\\ \\  ~~PAGEBREAK~~ ~~CLEARFIX~~
+===== 1.1 Amplifier - a Black Box is going to be specified =====
-<WRAP noprint>
-{{youtube>HC4NXIigD98?size=543x342}}
-</WRAP>
-Example 3 shows different amplifiers in interaction with a microcontroller. In addition to the evaluation of sensors, a signal output is necessary for many applications. If powerful motors, LEDs, antennas or loudspeakers are to be controlled, an amplifier must convert the microcontroller signal appropriately. In addition, an amplifier can take over control tasks analogously and usually with little electronic effort.
-\\ \\ ~~PAGEBREAK~~ ~~CLEARFIX~~
-<WRAP noprint>
-{{youtube>Ki_uU418-xQ?size=543x342}}
-</WRAP>
-~~PAGEBREAK~~ ~~CLEARFIX~~
-===== 1.2 Amplifier - a black box is going to be specified =====
-<WRAP noprint>
-{{youtube>wB498oinin4?size=543x302}} ~~PAGEBREAK~~ ~~CLEARFIX~~
-</WRAP>
 Before the amplifier is examined in more detail in the application, the interfaces and essential characteristics are to be dealt with first.
-<WRAP>
-The switching symbol of the amplifier is a rectangle with an inserted triangle. The input terminals on the left side are marked $IN+$ and $IN-$. The output terminals on the right side are correspondingly labeled $OUT+$ and $OUT-$. The input voltage $U_E$, or $U_{IN}$ is applied between the input terminals and the output voltage $U_A$, or $U_{OUT}$ is applied between the output terminals. \\ \\
-The signal to be amplified comes from any source on the left-hand side. Often this can be seen as an ideal (voltage) source - i.e. with internal resistance. The amplified signal is fed to a load on the right-hand side. In the simplest case, this load is an ohmic resistor. \\ \\
-</WRAP>
-<WRAP column 40%>
 <panel type="danger" title="Note!">
 <WRAP group><WRAP column 7%>{{fa>exclamation?32}}</WRAP><WRAP column 80%>
-An amplifier is a system that uses a low power input signal to control a much higher power output signal. \\ \\
+An amplifier is a system that uses a low-power input signal to control a much higher-power output signal. \\ \\
 The necessary energy is taken from the power supply!
 </WRAP></WRAP></panel>
-</WRAP>
 ~~PAGEBREAK~~ ~~CLEARFIX~~
 ==== Characteristics ====
-<WRAP right><panel type="default">
+Mostly, when an amplifier is used, it is specifically a voltage amplifier. Accordingly, the voltage amplifier is the basis for the following explanation. However, the determined values also apply to other amplifiers. In <imgref pic1> a voltage amplifier is shown as a black box. The voltage amplifier always tries to output a given multiple of the input voltage $U_\rm I$ (in German: //Eingangsspannung// $U_\rm E$) at the output as output voltage $U_\rm O$ (in German: //Ausgangsspannung// $U_\rm A$). This "multiple" can be determined as a ratio.
+<WRAP><panel type="default">
 <imgcaption pic1|Amplifier with source and load>
 </imgcaption>
-{{drawio>Ersatzschaltbild_eines_Verstärkers_Blackbox}}
+{{drawio>Ersatzschaltbild_eines_Verstärkers_Blackbox.svg}}
 </panel></WRAP>
-A voltage amplifier is required for most applications. Accordingly, this is the basis for the following explanation. However, the determined values apply also to other amplifiers. In <imgref pic1> a voltage amplifier is shown as a black box. The voltage amplifier always tries to output a given multiple of the input voltage $U_I$ (in German: Eingangsspannung $U_E$) at the output as output voltage $U_O$ (in German: Ausgangsspannung $U_A$). This "multiple" can be determined as a ratio. \\ \\
+The symbol of the amplifier is a rectangle with an inserted triangle. The input terminals on the left side are marked $\rm IN+$ and $\rm IN-$. The output terminals on the right side are correspondingly labeled $\rm OUT+$ and $\rm OUT-$. The input voltage $U_\rm I$ is applied between the input terminals and the output voltage $U_{\rm O}$ is applied between the output terminals.
-Below a simulation of an ideal amplifier is shown. The input source specifies the voltage to be amplified. The amplifier with amplification factor 100 has the connections for input and output voltage drawn in. On the right side a resistor is provided as load; this can be varied via a switch. \\ \\
+The signal to be amplified comes from any source on the left-hand side. Often this can be seen as an ideal (voltage) source - i.e. with internal resistance. The amplified signal is fed to a load on the right-hand side. In the simplest case, this load is an ohmic resistor.
+In <imgref pic001> a simulation of an ideal amplifier is shown. The input source specifies the voltage to be amplified. The amplifier with an amplification factor of 100 has the connections for input and output voltage are drawn in. On the right side, a resistor is provided as load; this can be varied via a switch. \\ \\
 ~~PAGEBREAK~~ ~~CLEARFIX~~
-<WRAP>{{url>https://www.falstad.com/circuit/circuitjs.html?running=false&cct=$+1+0.001+0.04723665527410147+50+5+43%0A368+288+192+288+160+0+0%0A368+-112+192+-112+160+0+0%0Aw+224+192+288+192+0%0Ax+260+101+305+104+4+24+Last%0Ab+252+115+377+367+0%0Ab+-206+114+-49+366+0%0Ax+-198+100+-129+103+4+24+Quelle%0Aw+192+288+224+288+0%0Ag+224+288+224+320+0%0Ar+288+288+288+192+0+100%0Aw+224+288+288+288+0%0A370+192+192+224+192+1+0%0Ag+-16+288+-16+320+0%0Ar+-112+192+-112+240+0+10000%0Aw+-16+288+-112+288+0%0Av+-112+288+-112+240+4+5+40+0.05+-0.025+0+0.5%0A370+-32+192+0+192+1+0%0Aw+-112+192+-32+192+0%0Aw+288+192+320+192+0%0Aw+288+288+336+288+0%0As+336+192+336+240+0+1+false%0Ar+336+240+336+288+0+100%0Aw+320+192+336+192+0%0Aw+144+224+144+192+0%0Aw+144+256+144+288+0%0Aw+48+256+48+288+0%0Aw+48+224+48+192+0%0A212+48+224+80+224+0+2+100*(a-b)%0Aw+16+288+-16+288+0%0Ab+16+114+173+366+0%0Ax+1+99+189+102+4+24+idealer%5CsVerst%C3%A4rker%0Aw+48+192+0+192+0%0Aw+48+288+16+288+0%0Aw+192+192+144+192+0%0Aw+192+288+144+288+0%0Ax+24+185+43+188+4+12+IN%5Cp%0Ax+26+303+41+306+4+12+IN-%0Ax+135+184+167+187+4+12+OUT%5Cp%0Ax+136+303+164+306+4+12+OUT-%0A 730,400 noborder}}
+<WRAP><well>
-</WRAP>
+<imgcaption pic001|Ideal Amplifier></imgcaption> \\
+{{url>https://www.falstad.com/circuit/circuitjs.html?running=false&ctz=CQAgjCAMB0mRNIBYDsAmAzANiwVl2ikmPKiLpOSEhuQKYC0YYAUNgBwhrudgCcaLj3BZKYtlk5Mwg-oOmzRUKCwDuXNEnAChvHZBYAPLkpIQMYWiS1bNIADIB7AIYATFgCMuBcGFwgMFBQArGCDLwY0SCxfLQYkPhCYg2MmPl44ECY0WUhaWy0AZUcAVwAnAGM6NW1Bbk4c22EDAHMNJoa7DCjlAzLdAfra5RIDdUbB4SGDQMo5YYn5hBU2phihtYCe8X6FYb3NMXA4OBrNjeY65pYANyzLgYOkSi1-Z6hYfwZENH8xaFwbBQlAY3WGcx0yzG9xk+zB82hQ3m3QhgkRU2EGGwAwMAGcAtjkdjDiMQAAzZwAG1x1X6WPW73pOOO0JRwyZCJqYCQtjs3K0nPU-O8MWF0xqSAauBikpxEs6Nj0aJYaFhsom7EoEy1LIAVAAKZwMDwASi562E52uXjAou54BQtGwySM4BAfESfggJEEBRAAEtXHQqQAdXEAQQAtgAHSn+sn+uhleXg8EppEWzjQpaQnlpoU6JF58XGPnsN5WYQCwQASQAciHo660DEMHlqOZotRwLW6wxXZZ-GB2ALQuB2MFqyAAPIAVQAKo2B9i21YsFo2zKezOF-2kJhlFEjtwECx97QtewIAx-C2-meD5eILe8CpUjkuDR7lqkFvhyBZ1dBgGgSLJbx8Kca2bLtNAaPxvAgKdpwHPgCjqGCkDeccAIfStb3YWQ+C1HAVHPcd8NkTUTBdMjh1veByKEZUgA noborder}}
+</well></WRAP>
 In the simulation some characteristics of an amplifier can be seen:
   - Ideally, no current flows into the amplifier on the input side.
   - The current on the output side depends on the connected load. If the load resistance is reduced with the help of the switch, the current increases. The amplifier thus tries to maintain the desired voltage.
-  - On the output side of the amplifier, the current can flow in either direction. \\ The amplifier adjusts the current so that the amplified voltage $U_A=\pm 2.5V$ can be measured at the output.
+  - On the output side of the amplifier, the current can flow in either direction. \\ The amplifier adjusts the current so that the amplified voltage $U_A=\pm 2.5~\rm V$ can be measured at the output.
 \\
@@ Zeile 118: / Zeile 83: @@
 <panel type="default" title="Characteristics" no-body="true">
 {{tablelayout?colwidth=""}}
-^ Characteristic groups^ #  ^ Characteristic (deutsch)                       ^ Characteristic (english)                                ^ Formula                            ^
+^ Characteristic groups^ #     ^ Characteristic (deutsch)                      ^ Characteristic (english)                                   ^ Formula                                        ^
-| Ratios ^ 1  | Spannungsverstärkung $A_V$               | Voltage Amplification $A_V$                             | $\large{A_V =\frac{U_A}{U_E}}$     |
+| Ratios                       ^ 1  | Spannungsverstärkung $A_{\rm V}$         | Voltage Amplification $A_{\rm V}$                          | $\large{A_{\rm V} =\frac{U_{\rm O}}{U_{\rm I}}}$   |
-| :::            ^ 2  | Stromverstärkung $A_C$                   | Current Amplification $A_C$                             | $\large{A_C =\frac{I_A}{I_E}}$     |
+| :::                          ^ 2  | Stromverstärkung     $A_{\rm C}$         | Current Amplification $A_{\rm C}$                          | $\large{A_{\rm C} =\frac{I_{\rm O}}{I_{\rm I}}}$   |
-| :::            ^ 3  | Übertragungswiderstand $R_ü$             | Transmission Resistance, \\ Transimpedance $R_T$           | $\large{R_ü =\frac{U_A}{I_E}}$     |
+| :::                          ^ 3  | Übertragungswiderstand $R_{\rm ü}$       | Transfer Resistance, \\ Transimpedance $R_{\rm T}$     | $\large{R_{\rm T} =\frac{U_{\rm O}}{I_{\rm I}}}$   |
-| :::            ^ 4  | Übertragungsleitwert (Steilheit) $G, S$  | Transmission Conductance, \\ Transconductance (Slope) $S$  | $\large{G = S = \frac{I_A}{U_E}}$  |
+| :::                          ^ 4  | Übertragungsleitwert (Steilheit) $G, S$  | Transfer Conductance, \\ Transconductance (Slope) $S$  | $\large{G    = S  =\frac{I_{\rm O}}{U_{\rm I}}}$   |
-| Input/Output Resistance ^ 5  | Eingangswiderstand $R_E$ | Input Resistance $R_I$  | $\large{R_E =\frac{U_E}{I_E}}$ |
+| Input/Output Resistance      ^ 5  | Eingangswiderstand   $R_{\rm E}$         | Input Resistance  $R_{\rm I}$                              | $\large{R_{\rm I} =\frac{U_{\rm I}}{I_{\rm I}}}$   |
-| :::                           ^ 6  | Ausgangswiderstand $R_A$ | Output Resistance $R_A$ | $\large{R_A =-\frac{\Delta U_A}{\Delta I_A}}$ |
+| :::                          ^ 6  | Ausgangswiderstand   $R_{\rm A}$         | Output Resistance $R_{\rm O}$                      | $\large{R_{\rm O} =-\frac{\Delta U_{\rm O}}{\Delta I_{\rm O}}}$  |
-| Reverse gains ^ 7  | Spannungsrückwirkung $A_{rV}$ | Reverse Voltage Gain  | $\large{A_{rV} =\frac{U_E}{U_A}}$ |
+| Reverse gains                ^ 7  | Spannungsrückwirkung $A_{\rm rV}$        | Reverse Voltage Gain                                       | $\large{A_{\rm rV} =\frac{U_{\rm I}}{U_{\rm O}}}$  |
-| :::         ^ 8  | Stromrückwirkung $A_{rC}$     | Reverse Current Gain  | $\large{A_{rC} =\frac{I_E}{I_A}}$ |
+| :::                          ^ 8  | Stromrückwirkung     $A_{\rm rC}$        | Reverse Current Gain                                       | $\large{A_{\rm rC} =\frac{I_{\rm I}}{I_{\rm O}}}$  |
 </panel>
 </WRAP>
 ~~PAGEBREAK~~ ~~CLEARFIX~~
-The ratios of the input and output quantities of a black box are called **characteristics**. A well-known parameter is, for example, the efficiency $\eta = \frac{P_A}{P_E}$. In the case of an amplifier, only the voltages and currents are considered as input and output quantities. Various amplifier parameters are shown in the table. \\
+The ratios of the input and output quantities of a black box are called **characteristics**. A well-known parameter is, for example, the efficiency $\eta = \frac{P_{\rm O}}{P_{\rm I}}$. In the case of an amplifier, only the voltages and currents are considered as input and output quantities. Various amplifier parameters are shown in the table. \\
-Different transmission ratios result, depending on the desired input variable and the output variable, which is to be controlled. It is important that the transfer resistance $R_ü$ and the transfer conductance $S$ do not correspond to any electrical component, since current and voltage are not measured at the same terminals. \\
+Different transmission ratios result, depending on the desired input variable and the output variable, which is to be controlled. It is important that the transmission resistance $R_\rm T$ and the transfer conductance $S$ do not correspond to any electrical component, since current and voltage are not measured at the same terminals.
-If current and voltage at the same terminals are put into relation, the input resistance $\boldsymbol{R_E}$ and the output resistance $R_A$ result. From [[:electrical engineering 1:start]] it is known that for an equivalent resistance of a system the quotient of open circuit voltage $U_{OC}$ and short circuit current $I_{SC}$ can be used. Important: A resistor must always be considered in the passive sign convention: For a (positive) resistance value, the current and voltage arrows must be plotted in the same direction. For input resistance this is already the case (see also <imgref pic1>).
-However, for output resistance $\boldsymbol{R_O}$ (in the amplifier), the arrow of $U_O$ and $I_O$ is antiparallel. The quotient is a negative value and must be negated accordingly. However, for the output resistance, the measurement of the short-circuit current $I_{O,SC}$ is also problematic. At the beginning of this subchapter it was already described that the voltage amplifier always tries to output a given multiple of the input voltage $U_I$ at the output as input voltage $U_O$. It would also attempt to do this in the event of a short circuit. The current $I_O$ would accordingly become very large. When measuring the short-circuit current $I_{O,SC}$, the disproportionately increasing losses $P=R_O\cdot I_O^2$ via the output resistance could then destroy the amplifier. Thus, determining the output resistance via the quotient of $U_O$ and $I_O$ is not possible. Since the output resistance is assumed to be an ohmic resistance - i.e. slope in the $U$-$I$ diagram - any two (load) points on the straight line can be used to form the quotient. Specifically, when measure the output resistance, one can measure the situation of the amplifier output with two different loads $R_{L,1}$ and $R_{L,2}$ and find the differences $\Delta U_O=U_{O,1}-U_{O,2}$ and $\Delta I_O=I_{O,1}-I_{O,2}$. \\
+When current and voltage at the same "side "are put into relation, the input resistance $\boldsymbol{R_{\rm I}}$ and the output resistance $R_\rm O$ result. From [[:electrical engineering 1:start]] it is known that an equivalent resistance of a system is given by the quotient of open circuit voltage $U_{\rm OC}$ and short circuit current $I_{\rm SC}$. Important: A resistor must always be considered in the passive sign convention: For a (positive) resistance value, the current and voltage arrows must be plotted in the same direction. For input resistance, this is already the case (see also <imgref pic1>).
-The most important characteristics of the voltage amplifier are the voltage gain $A_V$, as well as the input and output resistance $R_I$ and $R_O$.
+However, for output resistance $\boldsymbol{R_{\rm O}}$ (in the amplifier), the arrows of $U_\rm O$ and $I_\rm O$ are antiparallel. Therefore the fraction is a negative value. For getting a resistance value this fraction must be negated accordingly. However, for the measurement of the short-circuit current $I_{\rm O, SC}$ the output resistance is also often problematic. At the beginning of this subchapter, it was already described that the voltage amplifier always tries to output a given multiple of the input voltage $U_\rm I$ at the output as input voltage $U_\rm O$. It would also attempt to do this in the event of a short circuit. The current $I_\rm O$ would accordingly become very large. When measuring the short-circuit current $I_{\rm O, SC}$, the disproportionately increasing losses $P=R_O\cdot I_O^2$ via the output resistance could then destroy the amplifier. Thus, determining the output resistance via the quotient of $U_\rm O$ and $I_\rm O$ is not possible. Since the output resistance is assumed to be an ohmic resistance - i.e. slope in the $U$-$I$ diagram - any two (load) points on the straight line can be used to form the quotient. Specifically, when measuring the output resistance, one can measure the situation of the amplifier output with two different loads $R_{\rm L,1}$ and $R_{\rm L,2}$ and find the differences $\Delta U_{\rm O}=U_{\rm O,1}-U_{\rm O,2}$ and $\Delta I_{\rm O}=I_{\rm O,1}-I_{\rm O,2}$. \\
+The most important characteristics of the voltage amplifier are the voltage gain $A_\rm V$, as well as the input and output resistance $R_\rm I$ and $R_\rm O$.
 ~~PAGEBREAK~~ ~~CLEARFIX~~
-==== Equivalent circuit diagram ====
+==== Equivalent Circuit Diagram ====
-<WRAP right><panel type="default">
+<WRAP><panel type="default">
 <imgcaption pic2|Amplifier with source and load (with real voltage sources)>
 </imgcaption>
-{{drawio>Ersatzschaltbild_eines_Verstärkers}}
+{{drawio>Ersatzschaltbild_eines_Verstärkers.svg}}
 </panel></WRAP>
-After the view on the characteristics, the first attempt will be made to understand the internal structure of the amplifier. In the previous section, current-voltage relationships were determined from the external view. There, an input resistance $R_I$ was described on the input side of the amplifier. This is now taken into account in the equivalent circuit diagram (see <imgref pic2>). A resistance was also determined on the output side by considering it as a black box. Here, however, it must also be noted that the amplifier - according to its name - has to amplify the input signal. So here, besides the output resistor $R_O$, also an element has to be used, which outputs the amplified voltage. [(Note1>The voltage source used in the amplifier is a {{wp>dependent source}}, this term will not be discussed further in this course. )]. The voltage of the voltage source depends on the voltage applied to the input resistor $R_I$. It is more precisely larger by the factor of the voltage gain $A_V$. \\
+After the view on the characteristics, we try to understand the internal structure of the amplifier. Up to now, The current-voltage relationships were determined from the external view. There, an input resistance $R_\rm I$ was described on the input side of the amplifier. This is now taken into account in the equivalent circuit diagram (see <imgref pic2>). Resistance was also determined on the output side. Within the black box, however, it must also be noted that the amplifier - according to its name - has to amplify the input signal. So here, besides the output resistor $R_\rm O$, also an element has to be used, which outputs the amplified voltage. [(Note1>The voltage source used in the amplifier is a {{wp>dependent source}}, this term will not be discussed further in this course. )]. The voltage of the voltage source depends on the voltage applied to the input resistor $R_\rm I$. It is more precisely larger by the factor of the voltage gain $A_\rm V$. \\
 ~~PAGEBREAK~~ ~~CLEARFIX~~
-<WRAP right>{{url>https://www.falstad.com/circuit/circuitjs.html?running=false&ctz=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-1ktlisu8S9hgAHM-3UX9gXENASwvBg4gkT0uw9A8R3AOAv1dBD4N-dtvn-RtB3Aps1DAetINA58AOA-8sO7E921glNhyQBiQMvf56yomhmIAgA3OMMBrX8uNdKQ6FdGBIDoTRxIQOhL2vHC4ynJtGIZCD62Ywd4y9PsJHvL00FNbSYIkQyCIMntqKeBgwhMwIA3MliGQAM14MJC2dRCyNsrydM8wc0D0wdsJ0M9d2IA8wtpbxwAYBTDxo29dJbIiGBUcUVPSrzoqdPiMubIznS4wT8oAlQrTPANyqylL+z5BDTKwjs+X8wygoYAAjbsQxbX80EazrIX4kNk1dPqMG9Tryz0VN9wcchvSAA 730,400 noborder}}
+<WRAP>{{url>https://www.falstad.com/circuit/circuitjs.html?running=false&ctz=CQAgjCAMB0l5Amc0AsBmAnGLA2SGBWMFDADgzRBVJAKsoIFMBaMMAKGhAEsATRgIYAbAIIBbAA5gakEJRQgcIAJIA5ADoSqUEEjXMQAdjm6QAeQCqAFU20dlS1YM1KlAGoB9AMq224HZ5eBmBIEBAASowAztxRAC4A9gBOAKJCYupRYJkI6kmRMfHJaRlRuVFoeQWxianpmZVRKFXRNcX1UYaZpC2FtSWZYJCDeWYS4hKRwgNZ3YPDWdlZuUljEzONXWW9bXWlBPNQ6vPwmcMn8KdR51mXcGfHt-fXj0NX2WfQOI8o0GiGKAIkGwBEMCBQYCIhhYIVeNwWPUGB0yrGRT0uj1I0DALERUSxOOYeLeV3h0AQ7Ahsmo4AwoTwujB-j4glEkmkR3RsgWJLunN5cH58CFwqWMG+UVYhlgOHQ5DppFBkEMpEaQzOIB6WQOkshF1JsHg4IwAMMhgICAQYIIKEgzReXO5nwpAHddLbaUg0HbPVB2AAPXR0zUuQEgLDacEgAAyCQEvADIFYOCUpGMzAwskzkYUXgSAFckgBjRjsN0ISA0BCkGhgQxKasyMu6Su+utKbBISDNmmNuRIPvdt00zvgDvB7uBgip4zEDDh6nukATITcABm3EYSXY4XAIXAKAUbFC++5VFkkJ03OgBB3e69aA7+8fMh0HtRV6gN+bFarNfdsiDuwADmAG6P+4KyGgFZXuwSRyD6fbekeE7gHAP4ekhiH-t2-yAa2o6QW2OgcG60Hga+QGgYBOH9me3bwRm45IExYHXsCzY0TQrFAQAbkmGANv+PEegodAejAkB0MwkkIHQ163nhSZgMxY7EVBzasaOya+kOciPr6aAWrpcFyMZRFGQOtFvOwURmaEwaWWx-hrsIUSlmR2EuOZOHNshhkGaOuGGBe+7EEeYUMhAF7sEpx50fe+kdiR7BaFKqnpRR-iAZpgm+plQW5UJ3Htll3ZaLaF7BpVWXReAPaCkhPlNsOgqjk5hUAEb9uGHb-mgvndaweUmkmHoDfO3bddWxijYerjkH6QA noborder}}
 </WRAP>
-The simulation shows a **(simulated) real amplifier**. The input source has a high internal resistance. This means it has a high impedance and can only supply a small amount of current. The amplifier with a gain of 100 has - beside the connections for input and output voltage - also connections for the supply voltage drawn in. On the right side a resistor is provided as load; this can be varied via a switch.
+The simulation shows a **(simulated) real amplifier**. The input source has a high internal resistance. This means it has a high impedance and can only supply a small amount of current. The amplifier with a gain of 100 has - besides the connections for input and output voltage - also connections for the supply voltage drawn in. On the right side, a resistor is provided as load; this can be varied via a switch.
  ~~PAGEBREAK~~ ~~CLEARFIX~~
@@ Zeile 160: / Zeile 127: @@
   - The current on the output side depends on the connected load. If the load resistance is reduced with the help of the switch, the current increases. The amplifier thus tries to maintain the desired voltage.
   - The amplifier can output current as well as absorb current. \\ The current on the output side flows in and out of the amplifier through the supply voltage connections.
-  - The simulation is based on a real amplifier. This has a small deviation from the expected value $U_A=\pm 2.5V$ at the output voltage. Part of the deviation will be described later in this chapter.
+  - The simulation is based on a real amplifier. This has a small deviation from the expected value $U_{\rm O}=\pm 2.5~\rm V$ at the output voltage. Part of the deviation will be described later in this chapter.
 ~~PAGEBREAK~~ ~~CLEARFIX~~
 ==== Idealized Amplifier Base Types ====
+There are basic amplifier types depending on which input variable shall change which output variable. These are listed in the following table.
 <WRAP>
 <panel type="default" title="Idealized Amplifier Base Types" no-body="true">
 {{tablelayout?colwidth=""}}
-^ # ^ Amplifier              ^ Symbol                                  ^ $\boldsymbol{R_I}$                 ^ $\boldsymbol{R_O}$                 ^ gain ^
+^ # ^ Amplifier              ^ Symbol                                  ^ $\boldsymbol{R_\rm I}$                 ^ $\boldsymbol{R_\rm O}$                 ^ gain ^
-^ 1 | voltage amplifier       | {{spannungsverstaerker_bb.png?200}}(nbsp)(nbsp)(nbsp)(nbsp)      | \\ \\ $ \large{\rightarrow \infty}$(nbsp)(nbsp)(nbsp)(nbsp) | \\ \\ $ \large{\rightarrow 0}$      | \\ \\ $\large{A_V =\frac{U_O}{U_I}}$ |
+^ 1 | voltage amplifier            | {{drawio>voltageamp.svg}}(nbsp)(nbsp)(nbsp)(nbsp)      | \\ $ \large{\rightarrow \infty}$(nbsp)(nbsp)(nbsp)(nbsp) | \\ $ \large{\rightarrow 0}$      | \\ $\large{A_{\rm V} =\frac{U_\rm O}{U_\rm I}}$ |
-^ 2 | current amplifier       | {{stromverstaerker_bb.png?200}}          | \\ \\ $ \large{\rightarrow 0}$      | \\ \\ $ \large{\rightarrow \infty}$(nbsp)(nbsp)(nbsp)(nbsp) | \\ \\ $\large{A_C =\frac{I_O}{I_I}}$ |
+^ 2 | current amplifier            | {{drawio>currentamp.svg}}       | \\ $ \large{\rightarrow 0}$       | \\ $ \large{\rightarrow \infty}$(nbsp)(nbsp)(nbsp)(nbsp)  | \\ $\large{A_{\rm C} =\frac{I_\rm O}{I_\rm I}}$  |
-^ 3 | current-to-voltage converter | {{stromspannungsverstaerker_bb.png?200}} | \\ \\ $ \large{\rightarrow 0}$      | \\ \\ $ \large{\rightarrow 0}$      | \\ \\ $\large{R_ü =\frac{U_O}{I_I}}$ |
+^ 3 | current-to-voltage converter | {{drawio>voltagecurrconv.svg}}  | \\ $ \large{\rightarrow 0}$       | \\ $ \large{\rightarrow 0}$                               | \\ $\large{R_{\rm T} =\frac{U_\rm O}{I_\rm I}}$  |
-^ 4 | voltage-to-current converter | {{spannungsstromverstaerker_bb.png?200}} | \\ \\ $ \large{\rightarrow \infty}$ | \\ \\ $ \large{\rightarrow \infty}$ | \\ \\ $\large{S =\frac{I_O}{U_I}}$ |
+^ 4 | voltage-to-current converter | {{drawio>currvoltageconv.svg}}  | \\ $ \large{\rightarrow \infty}$  | \\ $ \large{\rightarrow \infty}$                          | \\ $\large{S =\frac{I_{\rm O}}{U_{\rm I}}}$    |
 </panel>
 </WRAP>
-Depending on which input variable shall change which output variable, different basic amplifier types result. These are listed in the table above. As a symbol in {{wp>block diagram}}s, a square with a diagonal is drawn for the respective basic amplifier type, which contains the corresponding formula symbol on the input and output side. \\ \\ Now the **input resistance** $\boldsymbol{R_I}$ and **output resistance** $\boldsymbol{R_O}$ for ideal voltage amplifiers shall be considered in more detail.
+As a symbol in {{wp>block diagram}}s, a square with a diagonal is drawn for the respective basic amplifier type, which contains the corresponding formula symbol on the input and output sides.
-If a voltage is th input, the input resistance should load the source as little as possible so that the voltage to be measured does not collapse (cf. <imgref pic2>). This can also be easily checked in the simulation of the real amplifier (see above). If the resistance of the load is increased there (double-click), it approaches the input resistance of the amplifier. If the value is set to $1 M \Omega $, the voltage collapses to half. The source resistance is then equal to the input resistance of the amplifier. It is therefore important that the input resistance is as high as possible, or ideally tends towards infinity. \\
-A similar consideration can be made for the **output resistance** $\boldsymbol{R_A}$. If a voltage is the output parameter, the output resistor must be dimensioned in such a way that the voltage at the load does not drop at the output either. The output resistance should be as small as possible so that the voltage dropping there becomes low.\\
+Now the **input resistance** $\boldsymbol{R_\rm I}$ and **output resistance** $\boldsymbol{R_\rm O}$ for ideal voltage amplifiers shall be considered in more detail.
+If a voltage is the input, the input resistance should load the source as little as possible so that the voltage to be measured does not drop (cf. <imgref pic2>). This can also be easily checked in the simulation of the real amplifier (see above). If the resistance of the load is increased there (double-click), it approaches the input resistance of the amplifier. If the value is set to $1 ~\rm M \Omega $, the voltage drops by half. The source resistance is then equal to the input resistance of the amplifier. It is therefore important that the input resistance is as high as possible, or ideally tends towards infinity. \\
+A similar consideration can be made for the **output resistance** $\boldsymbol{R_\rm O}$. If a voltage is the output parameter, the output resistor must be dimensioned in such a way that the voltage at the load does not drop at the output either. The output resistance should be as small as possible so that the voltage drop there becomes low.\\
 ~~PAGEBREAK~~ ~~CLEARFIX~~
-<WRAP right><panel type="default">
+<WRAP><panel type="default">
 <imgcaption pic3|Amplifier with source and load (with real current sources)>
 </imgcaption>
-{{drawio>Ersatzschaltbild_eines_Verstärkers_Stromquellen}}
+{{drawio>Ersatzschaltbild_eines_Verstärkers_Stromquellen.svg}}
 </panel></WRAP>
-Now, if the **input resistances** $\boldsymbol{R_E}$ **and output resistances** $\boldsymbol{R_A}$ **for __ideal current amplifiers__** are considered, a different view of the amplifier is favorable. In the <imgref pic3> the same amplifier considered so far can be seen. However, in this case all real voltage sources are replaced by real current sources. This transformation has already been described in [[Electrical Engineering 1:start]]. Depending on the considered electrical quantity, one or the other real source can be advantageous. \\ The input and output resistance of the current amplifier shall be considered with this knowledge. On the input side, most of the input current $I_I$ should flow into the amplifier. The input resistance $R_I$ must accordingly tend towards zero. The maximum current should also flow out of the amplifier at the amplifier output. Here, the output resistance $R_O$ must accordingly tend towards infinity, so that the lowest possible current flows through it.
+Now, if the **input resistances** $\boldsymbol{R_\rm I}$ **and output resistances** $\boldsymbol{R_\rm O}$ **for __ideal current amplifiers__** are considered, a different view of the amplifier is favorable. In the <imgref pic3> the same amplifier considered so far can be seen. However, in this case, all real voltage sources are replaced by real current sources. This transformation has already been described in [[Electrical Engineering 1:start]]. Depending on the considered electrical quantity, one or the other real source can be advantageous. \\ The input and output resistance of the current amplifier shall be considered with this knowledge. On the input side, most of the input current $I_\rm I$ should flow into the amplifier. The input resistance $R_\rm I$ must accordingly tend towards zero. The maximum current should also flow out of the amplifier at the amplifier output. Here, the output resistance $R_\rm O$ must accordingly tend towards infinity so that the lowest possible current flows through it.
 The following applies to **__current-voltage and voltage-current converters__**:
@@ Zeile 194: / Zeile 165: @@
 ~~PAGEBREAK~~ ~~CLEARFIX~~
-===== 1.3 Feedback =====
+===== 1.2 Feedback =====
-<WRAP right><panel type="default">
+<WRAP><panel type="default">
-<imgcaption pic4|Block diagram of a amplifier with feedback>
+<imgcaption pic4|Block diagram of an amplifier with feedback>
 </imgcaption>
-{{drawio>BlockschaltbildRueckkopplung}}
+{{drawio>BlockschaltbildRueckkopplung.svg}}
 </panel></WRAP>
-One of the fundamental principles of control engineering, digital technology and electronics is **feedback**. Thus, in the [[introduction to digital systems:start]], the output value of a NOR gate was already fed back to its input via detours for in order to create a flip-flop. Similarly, here the output value of the ideal amplifier is to be fed back to the input. In contrast to digital systems, in control engineering and electronics a fraction (in rare cases: a multiple) of the output value is fed back.\\
+One of the fundamental principles of control engineering, digital technology, and electronics is **feedback**. Thus, in the [[introduction to digital systems:start]], the output value of a NOR gate was already fed back to its input via detours in order to create a flip-flop. Similarly, here the output value of the ideal amplifier is to be fed back to the input. In contrast to digital systems, in control engineering and electronics a fraction (in rare cases: a multiple) of the output value is fed back.\\
-In addition, there is another tool for control engineering, digital systems and electronics: the **block diagram** or signal flow diagram. In [[Electrical Engineering 1:start]], circuit diagrams have been used so far. With circuit diagrams there is an interaction of all components due to Kirchhoff's rules, furthermore voltage differences everywhere or current can be measured over all components. \\
+In addition, there is another tool for control engineering, digital systems, and electronics: the **block diagram** or signal flow diagram. In [[Electrical Engineering 1:start]], only circuit diagrams have been used so far. With circuit diagrams there is an interaction of all components due to Kirchhoff's rules, furthermore, voltage differences everywhere or current can be measured over all components. \\
-In contrast to this is the block diagram. This shows individual blocks which link a cause with an effect. In general, no reaction of the effect on the cause is assumed. Causes and effects can be voltages or currents, which are then written on the respective connecting arrow. The block diagram does not claim to conserve energy or charge, but serves to provide an overview of the effects and interrelationships. Thus Kirchhoff's rules are usually not applicable there. \\
+In contrast to this is the block diagram. This shows individual blocks which link a cause with an effect. In general, no reaction of the effect on the cause is assumed. Causes and effects can be voltages or currents, which are then written on the respective connecting arrow. The block diagram does not claim to conserve energy or charge but serves to provide an overview of the effects and interrelationships. Thus Kirchhoff's rules are usually not applicable there. \\
-<imgref pic4> shows a block diagram of a feedback amplifier consisting of an ideal voltage amplifier with gain $A_D$ drawn in the center. The output voltage $U_O$, reduced by the factor $k$, is fed back via a feedback element. The circle symbol with the arithmetic symbols (in the block diagram on the left) shows how the incoming values must be offset against each other. The value $k \cdot U_O$ is thus subtracted from the input value $U_I$ in the indicated block diagram. \\ \\
+<imgref pic4> shows a block diagram of a feedback amplifier consisting of an ideal voltage amplifier with gain $A_\rm D$ drawn in the center. The output voltage $U_\rm O$, reduced by the factor $k$, is fed back via a feedback element. The circle symbol with the arithmetic symbols (in the block diagram on the left) shows how the incoming values must be offset against each other. The value $k \cdot U_\rm O$ is thus subtracted from the input value $U_\rm I$ in the indicated block diagram. \\ \\
-The advantage of a real amplifier in negative feedback is that the gain $A_V$ of the whole system depends only negligibly on the gain factor $A_D$ of the real amplifier, if $A_D$ is very large (see also task 1.3.2). In this case, the gain $A_V=\frac{1}{k}$. To avoid oscillation of the whole system, the amplifier must contain a delay element. This is present in the real amplifier in such a way that the output voltage $U_O$ cannot change infinitely fast. [(Note2>That a voltage change can only take place in finitely long time is also true for the input voltage. However, this cannot be influenced by the amplifier, but is externally specified.
+The advantage of a real amplifier in negative feedback is that the gain $A_\rm V$ of the whole system depends only negligibly on the gain factor $A_\rm D$ of the real amplifier if $A_\rm D$ is very large (see also task 1.3.2). In this case, the gain $ A_{\rm V}=\frac {1}{k}$. To avoid oscillation of the whole system, the amplifier must contain a delay element. This is present in the real amplifier in such a way that the output voltage $U_\rm O$ cannot change infinitely fast. [(Note2>That a voltage change can only take place in a finitely long time is also true for the input voltage. However, this cannot be influenced by the amplifier, but is externally specified.)] (see also task 1.3.1).
-)] (see also task 1.3.1).
 <WRAP column 80%>
 <panel type="danger" title="Note: feedback, positive feedback, negative feedback">
@@ Zeile 214: / Zeile 184: @@
 **__Feedback__** (German: **__Rückkopplung__**) refers to the return of part of the output signal of an amplifier. \\
-With **__positive__** (German: **__Mitkopplung__**) feedback, the part of the output signal with positive sign is fed back.
+With **__positive__** (German: **__Mitkopplung__**) feedback, the part of the output signal with a positive sign is fed back.
 The output value is therefore always increased by the input value.
 \\ \\
@@ Zeile 227: / Zeile 197: @@
 <panel type="danger" title="Note: Gain factors">
 <WRAP group><WRAP column 3%>{{fa>exclamation?32}}</WRAP><WRAP column 85%>
-The **differential gain** or **open-loop gain** $\boldsymbol{A_D}$ (German: Differenzverstärkung) refers only to input and output voltage of the inner amplifier: $A_D=\frac{U_O}{U_D}$.
+The **differential gain** or **open-loop gain** $\boldsymbol{A_\rm D}$ (German: Differenzverstärkung) refers only to the input and output voltage of the inner amplifier: $A_{\rm D}=\frac{U_\rm O}{U_\rm D}$.
 This acts only without external feedback. It is also called open-loop gain. \\ \\
-The **voltage gain** $\boldsymbol{A_V}$ refers to input and output voltage of the whole circuit with feedback: $A_V=\frac{U_O}{U_I}$. \\ It is also called closed-loop gain. \\ \\
+The **voltage gain** $\boldsymbol{A_\rm V}$ refers to the input and output voltage of the whole circuit with feedback: $A_{\rm V}=\frac{U_\rm O}{U_\rm I}$. \\ It is also called closed-loop gain. \\ \\
 </WRAP></WRAP></panel>
 </WRAP>
@@ Zeile 239: / Zeile 209: @@
 ====== Exercises ======
-{{page>Übungsblatt1&nofooter}}
+{{page>exercise_sheet_1&nofooter}}
-{{page>Übungsblatt2&nofooter}}
+{{page>exercise_sheet_2&nofooter}}
-====== Learning questions ======
+====== Learning Questions ======
-=== for your self-study ===
+=== for your Self-Study ===
   * What is the definition of an amplifier?
   * Explain with an example what is the essence of an amplifier.
@@ Zeile 251: / Zeile 221: @@
   * When is it called positive feedback and when is it called negative feedback?
   * Explain the principle of negative feedback.
-  * What is the difference between voltage gain and differential gain? Briefly describe the difference between $A_V$ and $A_D$.
+  * What is the difference between voltage gain and differential gain? Briefly describe the difference between $A_\rm V$ and $A_\rm D$.
-  * How does $A_D$ affect the output voltage $U_O$ when there is no feedback in an op-amp circuit?
+  * How does $A_\rm D$ affect the output voltage $U_\rm O$ when there is no feedback in an op-amp circuit?
-  * What is the effect of $A_D$ on the output voltage $U_O$ when feedback is present in an op-amp circuit and $A_D$ is increased from 100,000 to 200,000?
+  * What is the effect of $A_\rm D$ on the output voltage $U_\rm O$ when feedback is present in an op-amp circuit and $A_\rm D$ is increased from $100'000$ to $200'000$?
   * At what value for k does the feedback become maximum?
-  * What values can k take for a passively feedback amplifier?
+  * What values can k take for a passive feedback amplifier?
   * What effect does k have on the amplifier?
   * What happens if you feed back the entire output voltage?
-=== with answers ===
+=== with Answers ===
-<quizlib id="quiz" rightanswers="[['a3'],['a3'], ['a1'], ['a3'], ['a0', 'a3']]" submit="check answers">
+<WRAP group>
-    <question title="How is the output resistance of an amplifier defined?" type="checkbox">
+<WRAP column half>
-$R_O = \Delta U_I / \Delta I_O$|
-$R_O = U_I / I_O$|
+<WRAP hide> <quizlib id="dummy" rightanswers="[[]]" submit="x"></quizlib> Only necessary to eliminate the score bar... </WRAP>
-$R_O = \Delta U_O / \Delta I_O$|
-$R_O = -\Delta U_O / \Delta I_O$|
-$R_O =  U_O / I_O$
+{{page>circuit_design:1_quiz_1.1.0&nofooter}}
-</question>
+{{page>circuit_design:1_quiz_1.1.1&nofooter}}
-    <question title="Ideal resistances of a voltage-current converter" type="checkbox">
-$R_I → 0$, $R_O → ∞$|
+<panel type="info" title="Exercise - Quiz"> <WRAP group><WRAP column 2%>{{fa>pencil?32}}</WRAP><WRAP column 88%>
-$R_I → 0$, $R_O → 0$|
+<quizlib id="quiz3" rightanswers="[['a3']]" submit="check answers">
-$R_I → ∞$, $R_O → 0$|
+    <question title="What type of amplifier produces an output current $I_\rm O$ from an input voltage $U_\rm I$, such that an output voltage $U_\rm O = k \cdot U_\rm I$ with constant $k$ is produced?" type="checkbox">
-$R_I → ∞$, $R_O → ∞$
-</question>
-    <question title="What can you use a linear regulator for?" type="checkbox">
-To regulate linear motors |
-To output fixed voltage values |
-To regulate linear circuits|
-To output fixed current values
-</question>
-    <question title="What type of amplifier produces an output current $I_O$ from an input voltage $U_I$, such that an output voltage $U_O = C \cdot U_I$ with constant $C$ is produced?" type="checkbox">
 Current-to-voltage converter|
 Current amplifier|
 Voltage-to-current converter|
 Voltage amplifier
-</question>
+</question></quizlib></WRAP></WRAP></panel>
+</WRAP><WRAP column half>
+<panel type="info" title="Exercise - Quiz"> <WRAP group><WRAP column 2%>{{fa>pencil?32}}</WRAP><WRAP column 88%>
+<quizlib id="quiz4" rightanswers="[['a0', 'a3']]" submit="check answers">
     <question title="The transfer resistance ..." type="checkbox">
 Cannot be measured using a resistance meter|
 Can be used for voltage dividers|
-Is given by ${U_E} \over {I_A}$, with input voltage $U_I$ and output current $I_O$|
+Is given by ${U_\rm I} \over {I_\rm O}$, with input voltage $U_\rm I$ and output current $I_\rm O$|
 represents the gain
-</question>
+</question></quizlib></WRAP></WRAP></panel>
-</quizlib>
+<panel type="info" title="Exercise - Quiz"> <WRAP group><WRAP column 2%>{{fa>pencil?32}}</WRAP><WRAP column 88%>
+<quizlib id="quiz5" rightanswers="[['a0','a3']]" submit="check answers">
+    <question title="An amplifier circuit..." type="checkbox">
+...  needs an additional power supply for the amplification.|
+... can only be built with positive feedback. |
+... controls by an input circuit with high power output with small power.|
+... has to include a voltage divider
+</question></quizlib></WRAP></WRAP></panel>
+</WRAP>