| Name | |
|---|---|
| Student ID number | |
The aim of this experiment is to become familiar with and investigate the following:
Procedure for voltage measurement:
Procedure for current measurement:
Procedure for resistance measurement:
The Agilent U1241A multimeter has automatic range selection. The following measuring ranges are available:
| Function | Range | Accuracy |
|---|---|---|
| DC voltage | $0 \ldots 1000 ~{\rm V}$ | $\pm 0.1 \%$ |
| AC voltage | $0 \ldots 1000 ~{\rm V}$ | $\pm 1 \%$ |
| DC current | $0 \ldots 10 ~{\rm A}$ | $\pm 0.2 \%$ |
| AC current | $0 \ldots 10 ~{\rm A}$ | $\pm 1 \%$ |
| Resistance | $0 \ldots 100 ~{\rm M}\Omega$ | $\pm 0.3 \%$ |
| Capacitance | $0 \ldots 10 ~{\rm mF}$ | $\pm 1.2 \%$ |
| Frequency | $30 ~{\rm Hz} \ldots 100 ~{\rm kHz}$ | $\pm 0.3 \%$ |
| Quantity | Symbol | Unit | Unit symbol |
|---|---|---|---|
| Voltage, potential difference | $U$ | volt $= {\rm W}\cdot{\rm A}^{-1} = {\rm kg}\cdot{\rm m}^2\cdot{\rm s}^{-3}\cdot{\rm A}^{-1}$ | ${\rm V}$ |
| Current | $I$ | ampere (base unit) | ${\rm A}$ |
| Resistance | $R$ | ohm $= {\rm V}\cdot{\rm A}^{-1} = {\rm kg}\cdot{\rm m}^2\cdot{\rm s}^{-3}\cdot{\rm A}^{-2}$ | $\Omega$ |
Conventional current direction: current flows from positive to negative.
Determine the nominal value and the measured value of the resistance of $R_1$ (brown, green, orange), $R_2$ (yellow, violet, red), $R_3$ (red, violet, red) and the incandescent lamp $R_{\rm L}$. Also measure the approximate resistance $R_{\rm K}$ of your body from your right hand to your left hand.
| $R_1$ | $R_2$ | $R_3$ | $R_{\rm L}$ | $R_{\rm K}$ | |
|---|---|---|---|---|---|
| Nominal value | |||||
| Measured value |
How do you explain the deviation between $R_{\rm L,nom}$ and $R_{\rm L,meas}$?
What consequences can $R_{\rm K}$ have?
Now also determine the series and parallel combinations of resistors $R_1$, $R_2$ and $R_3$. State the formulae used:
$R_{\rm series} = R_{\rm a} + R_{\rm b}$
$R_{\rm parallel} = (R_{\rm a} \parallel R_{\rm b}) = \frac{R_{\rm a} \cdot R_{\rm b}}{R_{\rm a} + R_{\rm b}}$
| $R_1 + R_2$ | $R_1 + R_3$ | $R_2 + R_3$ | $R_1 \parallel R_2$ | $R_1 \parallel R_3$ | $R_2 \parallel R_3$ | |
|---|---|---|---|---|---|---|
| Calculated | ||||||
| Measured |
Resistance can also be determined by a current/voltage measurement.
Ohm's law: In a circuit, the current increases with increasing voltage and decreases with increasing resistance.
$ I = \frac{U}{R} $
Build the measurement circuit shown in Figure 2 for each of the three resistors and set the voltage on the bench power supply to $12 ~{\rm V}$.
Measure $U_n$ and $I_n$. From these values calculate $R_n$ in each case.
| $I_1 / {\rm mA}$ | $U_1 / {\rm V}$ | $R_1 / {\rm k}\Omega$ | $I_2 / {\rm mA}$ | $U_2 / {\rm V}$ | $R_2 / {\rm k}\Omega$ | $I_3 / {\rm mA}$ | $U_3 / {\rm V}$ | $R_3 / {\rm k}\Omega$ |
|---|---|---|---|---|---|---|---|---|
In every closed circuit and in every supply loop, the sum of all voltages is zero.
Set the voltage on the bench power supply to $12 ~{\rm V}$ and measure this voltage accurately with a multimeter. Build the measurement circuit shown in Figure 3.
Complete the voltage arrows and measure $U$, $U_1$ and $U_2$.
| $U$ | $U_1$ | $U_2$ |
|---|---|---|
What is the loop equation here?
Verify the formula using the measured values:
The resistors $R_1$ and $R_2$ connected in series form a voltage divider. In what ratio are the voltages $U_1$ and $U_2$?
$U_1 / U_2 =$
$=$
At every branch point, the sum of all currents flowing into and out of the node is zero.
Set the voltage on the bench power supply to $12 ~{\rm V}$ and measure the voltage accurately with a multimeter. As a first step, build the measurement circuit shown in Figure 4.
Draw the arrows for the directions of currents $I_1$ and $I_2$ in Figure 4. On both multimeters the DC current range and the polarity must be set before switching on. Then measure currents $I_1$ and $I_2$ and enter the measured values in Table 5.
In what ratio are currents $I_1$ and $I_2$?
$I_1 / I_2 =$
$=$
Switch the bench power supply on again and measure the current $I$. Enter its value in Table 5.
| $I$ | $I_1$ | $I_2$ |
|---|---|---|
Determine the node equation for node $K$ and verify its validity.
Using the measured values of resistors $R_1$, $R_2$ and $R_3$, calculate the total resistance $R_{\rm KP}$.
Using the calculated value of $R_{\rm KP}$, verify the measured value of the total current:
$I = \frac{U}{R_{\rm KP}} =$
$=$
The voltage divider shown in Figure 6 is initially in the unloaded condition, because the entire current supplied by the bench power supply flows through the series-connected resistors $R_1$ and $R_2$. A resistor connected in parallel with $R_2$ loads the voltage divider.
Set the voltage on the bench power supply to $12 ~{\rm V}$ and measure the exact voltage with a multimeter. Build the measurement circuit shown in Figure 6.
For the connected load $R_{\rm L} = 10 ~{\rm k}\Omega$, the voltage divider represents a voltage source. Like any voltage source, it has a source voltage (open-circuit voltage) $U_0$ and an internal resistance $R_{\rm i}$. The internal resistance of the voltage divider, regarded as a voltage source, results from the parallel connection of divider resistors $R_1$ and $R_2$:
$R_{\rm i} = R_1 \parallel R_2 = \frac{R_1 \cdot R_2}{R_1 + R_2}$
Using the measured values of resistors $R_1$ and $R_2$, calculate the internal resistance of the voltage source and determine the source voltage:
$R_{\rm i} =$
$U_0 =$
The power supplied by the bench power supply $P_0$ can be calculated using the following equation:
$P_0 = U \cdot I_1$
The power consumed by the load resistor can be determined using the following equation:
$P_{\rm L} = R_{\rm L} \cdot I_2^2$
Draw the equivalent voltage source of the voltage divider:
What value would $U_2$ have without $R_{\rm L}$?
$U_{2,0} =$
Calculate $U_{2{\rm L}}$ and $I_2$ for $R_{\rm L} = 10 ~{\rm k}\Omega$ using the values of the equivalent voltage source. State the formulae used.
$U_{2{\rm L}}:$
$I_2:$
Verify the values by measurement:
$U_{2{\rm L},meas}:$
$I_{2,{\rm meas}}:$
Verify the values using Kirchhoff's laws. State the formulae used.
$U_{2{\rm L}}:$
$I_2:$
All resistors investigated so far are linear resistors, for which the characteristic $I = f(U)$ is a straight line. See Figure 7. The resistance value of a linear resistor is independent of the current $I$ flowing through it or of the applied voltage $U$.
For non-linear resistors there is no proportionality between current and voltage. The characteristic of such a resistor is shown in Figure 8. For these resistors one speaks of the static resistance $R$ and the dynamic (or differential) resistance $r$.
The static resistance is determined for a particular operating point: at a given voltage, the current is read from the resistance characteristic. The calculation is carried out according to Ohm's law:
$R = \frac{U}{I}$
The differential resistance around the operating point is calculated from the current difference caused by a change in the applied voltage:
$r = \frac{\Delta U}{\Delta I}$
As an example of a non-linear resistor, an incandescent lamp is investigated. Build the measurement circuit shown in Figure 9.
Set the bench power supply to the voltage values from Table 7. Measure the corresponding current values and enter them in Table 7.
| $U / {\rm V}$ | 0.5 | 1.0 | 2.0 | 3.0 | 4.0 | 5.0 | 6.0 | 7.0 | 8.0 |
|---|---|---|---|---|---|---|---|---|---|
| $I / {\rm mA}$ |
Plot the characteristic $I = f(U)$.
Calculate the static resistance $R$ at the operating point $U = 7.0 ~{\rm V}$.
Calculate the dynamic resistance $r$ at the operating point $U = 7.0 ~{\rm V}$.
Compare the values with those from Section 1.2 (direct resistance measurement).