The circuits previously analyzed individually are now connected to form a complete system.
The integrator and the Schmitt trigger together form an oscillator. The output signal
of the Schmitt trigger is fed back to the input of the integrator. Therefore, the output
signal simultaneously acts as the input signal of the overall system.
Due to this feedback, the circuit generates a periodic signal without requiring an external
input signal, apart from the supply voltages of the operational amplifiers.
The Schmitt trigger generates a rectangular signal that is integrated into a triangular signal
until one of the switching thresholds is reached. At this point, the output state changes
and the process repeats continuously, producing a stable oscillation.
When the circuit is first powered on, the oscillator starts due to small disturbances such
as noise, offset voltages of the operational amplifiers, or slight asymmetries in the circuit.
These small deviations move the system away from the unstable equilibrium point and initiate
the oscillation.
To analyze the behavior of the oscillator (triangle-rectangle generator), the following circuit is used:
Supply voltages (from power supply unit):
UCC = + 3V, UEE = - 3V
Values of the components used:
R1 = 200 kΩ, R1.3 = 10 kΩ, R2 = 20 kΩ, R3 = 27 kΩ, C1 = 10 nF
C1 = 10 nF, f = ƒmin
Channel 1: $\frac {Volt}{Div}=$
Channel 2: $\frac {Volt}{Div}=$
Time basis: $\frac {T}{Div}=$
C1 = 10 nF, f = ƒmax
Channel 1: $\frac {Volt}{Div}=$
Channel 2: $\frac {Volt}{Div}=$
Time basis: $\frac {T}{Div}=$
C1 = 1 nF, f = ƒmin
Channel 1: $\frac {Volt}{Div}=$
Channel 2: $\frac {Volt}{Div}=$
Time basis: $\frac {T}{Div}=$
C1 = 1 nF, f = ƒmax
Channel 1: $\frac {Volt}{Div}=$
Channel 2: $\frac {Volt}{Div}=$
Time basis: $\frac {T}{Div}=$
3. Explain how this circuit works in a few sentences.
4. Why is it useful to use R1 as a potentiometer to vary the frequency rather than R2
or R3?