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-====== Experiment 1 ====== 
-===== DC circuit theory ===== 
-==== Linear and non-linear resistors ==== 
  
-^ Name ^ <wrap onlyprint> \\ \\ </wrap> ^ 
-^ Student ID number ^ <wrap onlyprint> \\ \\ </wrap> ^ 
- 
-=== Equipment used === 
- 
-  * Bench power supply GPS 3303 
-  * Digital multimeter Agilent U1241A 
-  * Breadboard GL-36 
-  * Decade resistance box RD-1000, $\pm 1 \%$ 
- 
-The aim of this experiment is to become familiar with and investigate the following: 
- 
-  * assembling simple circuits on the GL-36 breadboard 
-  * carrying out measurements with the Agilent U1241A digital multimeter 
-  * using resistor standard series and the associated colour codes 
-  * measuring resistances, voltages and currents 
- 
-==== General measurement techniques ==== 
- 
-=== Voltage measurement === 
- 
-Procedure for voltage measurement: 
- 
-  - Set the meter to the largest voltage range (check whether direct voltage or alternating voltage is to be measured; not necessary in auto range). 
-  - Connect the test leads to the correct meter sockets (the sockets marked COM and V). 
-  - Connect the test leads to the component under test with the correct polarity, so that the meter is connected in parallel with the component. 
-  - Read the measured value. 
- 
-=== Current measurement === 
- 
-Procedure for current measurement: 
- 
-  - Set the meter to the largest current range (check whether direct current or alternating current is to be measured; not necessary in auto range). 
-  - Connect the test leads to the correct meter sockets (the sockets marked COM and $\mu{\rm A}.{\rm mA}$). 
-  - Connect the test leads to the component under test with the correct polarity, so that the meter is connected in series with the component. 
-  - Read the measured value. 
- 
-=== Resistance measurement === 
- 
-Procedure for resistance measurement: 
- 
-  - Set the meter to resistance measurement. 
-  - Connect the resistor to be measured to the corresponding sockets on the meter (the sockets marked COM and $\Omega$). 
-  - Read the measured value. 
- 
-=== Digital multimeter Agilent U1241A === 
- 
-The Agilent U1241A multimeter has automatic range selection. The following measuring ranges are available: 
- 
-^ Function ^ Range ^ Accuracy ^ 
-| DC voltage | $0 \ldots 1000 ~{\rm V}$ | $\pm 0.1 \%$ | 
-| AC voltage | $0 \ldots 1000 ~{\rm V}$ | $\pm 1 \%$ | 
-| DC current | $0 \ldots 10 ~{\rm A}$ | $\pm 0.2 \%$ | 
-| AC current | $0 \ldots 10 ~{\rm A}$ | $\pm 1 \%$ | 
-| Resistance | $0 \ldots 100 ~{\rm M}\Omega$ | $\pm 0.3 \%$ | 
-| Capacitance | $0 \ldots 10 ~{\rm mF}$ | $\pm 1.2 \%$ | 
-| Frequency | $30 ~{\rm Hz} \ldots 100 ~{\rm kHz}$ | $\pm 0.3 \%$ | 
- 
-=== Physical quantities and units used === 
- 
-^ Quantity ^ Symbol ^ Unit ^ Unit symbol ^ 
-| Voltage, potential difference | $U$ | volt $= {\rm W}\cdot{\rm A}^{-1} = {\rm kg}\cdot{\rm m}^2\cdot{\rm s}^{-3}\cdot{\rm A}^{-1}$ | ${\rm V}$ | 
-| Current | $I$ | ampere (base unit) | ${\rm A}$ | 
-| Resistance | $R$ | ohm $= {\rm V}\cdot{\rm A}^{-1} = {\rm kg}\cdot{\rm m}^2\cdot{\rm s}^{-3}\cdot{\rm A}^{-2}$ | $\Omega$ | 
- 
-Conventional current direction: current flows from positive to negative. 
- 
-==== Direct resistance measurement ==== 
- 
-Determine the nominal value and the measured value of the resistance of $R_1$ (brown, green, orange), $R_2$ (yellow, violet, red), $R_3$ (red, violet, red) and the incandescent lamp $R_{\rm L}$. Also measure the approximate resistance $R_{\rm K}$ of your body from your right hand to your left hand. 
- 
-^  ^ $R_1$ ^ $R_2$ ^ $R_3$ ^ $R_{\rm L}$ ^ $R_{\rm K}$ ^ 
-| Nominal value |  |  |  |  |  | 
-| Measured value |  |  |  |  |  | 
- 
-How do you explain the deviation between $R_{\rm L,nom}$ and $R_{\rm L,meas}$? 
-<wrap onlyprint> \\ \\ \\ \\ </wrap> 
- 
-What consequences can $R_{\rm K}$ have? 
-<wrap onlyprint> \\ \\ \\ \\ </wrap> 
- 
-Now also determine the series and parallel combinations of resistors $R_1$, $R_2$ and $R_3$. State the formulae used: 
- 
-$R_{\rm series} = R_{\rm a} + R_{\rm b}$ 
- 
-$R_{\rm parallel} = (R_{\rm a} \parallel R_{\rm b}) = \frac{R_{\rm a} \cdot R_{\rm b}}{R_{\rm a} + R_{\rm b}}$ 
- 
-^  ^ $R_1 + R_2$ ^ $R_1 + R_3$ ^ $R_2 + R_3$ ^ $R_1 \parallel R_2$ ^ $R_1 \parallel R_3$ ^ $R_2 \parallel R_3$ ^ 
-| Calculated |  |  |  |  |  |  | 
-| Measured |  |  |  |  |  |  | 
- 
-==== Indirect resistance measurement ==== 
- 
-Resistance can also be determined by a current/voltage measurement. 
- 
-**Ohm's law:** In a circuit, the current increases with increasing voltage and decreases with increasing resistance. 
- 
-\\ 
-$ I = \frac{U}{R} $ 
-\\ 
- 
-Build the measurement circuit shown in Figure 2 for each of the three resistors and set the voltage on the bench power supply to $12 ~{\rm V}$. 
- 
-{{drawio>lab_electrical_engineering:1_dc_circuit_theory:figure_2_indirect_resistance_measurement.svg}} 
- 
-Measure $U_n$ and $I_n$. From these values calculate $R_n$ in each case. 
- 
-^ $I_1 / {\rm mA}$ ^ $U_1 / {\rm V}$ ^ $R_1 / {\rm k}\Omega$ ^ $I_2 / {\rm mA}$ ^ $U_2 / {\rm V}$ ^ $R_2 / {\rm k}\Omega$ ^ $I_3 / {\rm mA}$ ^ $U_3 / {\rm V}$ ^ $R_3 / {\rm k}\Omega$ ^ 
-|  |  |  |  |  |  |  |  |  | 
- 
-==== Kirchhoff's voltage law (loop law) ==== 
- 
-In every closed circuit and in every supply loop, the sum of all voltages is zero. 
- 
-Set the voltage on the bench power supply to $12 ~{\rm V}$ and measure this voltage accurately with a multimeter. Build the measurement circuit shown in Figure 3. 
- 
-{{drawio>lab_electrical_engineering:1_dc_circuit_theory:figure_3_loop_law.svg}} 
- 
-Complete the voltage arrows and measure $U$, $U_1$ and $U_2$. 
- 
-^ $U$ ^ $U_1$ ^ $U_2$ ^ 
-|  |  |  | 
- 
-What is the loop equation here? 
-<wrap onlyprint> \\ \\ \\ \\ </wrap> 
- 
-Verify the formula using the measured values: 
-<wrap onlyprint> \\ \\ \\ \\ </wrap> 
- 
-The resistors $R_1$ and $R_2$ connected in series form a voltage divider. In what ratio are the voltages $U_1$ and $U_2$? 
- 
-$U_1 / U_2 =$ <wrap onlyprint> \\ \\ </wrap> $=$ <wrap onlyprint> \\ \\ </wrap> 
- 
-==== Kirchhoff's current law (node law) ==== 
- 
-At every branch point, the sum of all currents flowing into and out of the node is zero. 
- 
-Set the voltage on the bench power supply to $12 ~{\rm V}$ and measure the voltage accurately with a multimeter. As a first step, build the measurement circuit shown in Figure 4. 
- 
-{{drawio>lab_electrical_engineering:1_dc_circuit_theory:figure_4_branch_currents.svg}} 
- 
-Draw the arrows for the directions of currents $I_1$ and $I_2$ in Figure 4. On both multimeters the DC current range and the polarity must be set before switching on. Then measure currents $I_1$ and $I_2$ and enter the measured values in Table 5. 
- 
-{{drawio>lab_electrical_engineering:1_dc_circuit_theory:figure_4_total_current_and_node_K.svg}} 
- 
-In what ratio are currents $I_1$ and $I_2$? 
- 
-$I_1 / I_2 =$ <wrap onlyprint> \\ \\ </wrap> $=$ <wrap onlyprint> \\ \\ </wrap> 
- 
-Switch the bench power supply on again and measure the current $I$. Enter its value in Table 5. 
- 
-^ $I$ ^ $I_1$ ^ $I_2$ ^ 
-|  |  |  | 
- 
-Determine the node equation for node $K$ and verify its validity. 
-<wrap onlyprint> \\ \\ \\ \\ </wrap> 
- 
-Using the measured values of resistors $R_1$, $R_2$ and $R_3$, calculate the total resistance $R_{\rm KP}$. 
-<wrap onlyprint> \\ \\ \\ \\ </wrap> 
- 
-Using the calculated value of $R_{\rm KP}$, verify the measured value of the total current: 
- 
-$I = \frac{U}{R_{\rm KP}} =$ <wrap onlyprint> \\ \\ </wrap> $=$ <wrap onlyprint> \\ \\ </wrap> 
- 
-==== Voltage divider as a voltage source (a) ==== 
- 
-The voltage divider shown in Figure 6 is initially in the unloaded condition, because the entire current supplied by the bench power supply flows through the series-connected resistors $R_1$ and $R_2$. A resistor connected in parallel with $R_2$ loads the voltage divider. 
- 
-Set the voltage on the bench power supply to $12 ~{\rm V}$ and measure the exact voltage with a multimeter. Build the measurement circuit shown in Figure 6. 
- 
-For the connected load $R_{\rm L} = 10 ~{\rm k}\Omega$, the voltage divider represents a voltage source. Like any voltage source, it has a source voltage (open-circuit voltage) $U_0$ and an internal resistance $R_{\rm i}$. The internal resistance of the voltage divider, regarded as a voltage source, results from the parallel connection of divider resistors $R_1$ and $R_2$: 
- 
-\\ 
-$R_{\rm i} = R_1 \parallel R_2 = \frac{R_1 \cdot R_2}{R_1 + R_2}$ 
-\\ 
- 
-Using the measured values of resistors $R_1$ and $R_2$, calculate the internal resistance of the voltage source and determine the source voltage: 
- 
-$R_{\rm i} =$ <wrap onlyprint> \\ \\ </wrap> \\ 
-$U_0 =$ <wrap onlyprint> \\ \\ </wrap> 
- 
-The power supplied by the bench power supply $P_0$ can be calculated using the following equation: 
- 
-\\ 
-$P_0 = U \cdot I_1$ 
-\\ 
- 
-The power consumed by the load resistor can be determined using the following equation: 
- 
-\\ 
-$P_{\rm L} = R_{\rm L} \cdot I_2^2$ 
-\\ 
- 
-{{drawio>lab_electrical_engineering:1_dc_circuit_theory:figure_6_loaded_voltage_divider.svg}} 
- 
-==== Voltage divider as a voltage source (b) ==== 
- 
-Draw the equivalent voltage source of the voltage divider: 
- 
-{{drawio>lab_electrical_engineering:1_dc_circuit_theory:figure_6b_equivalent_voltage_source.svg}} 
- 
-What value would $U_2$ have without $R_{\rm L}$? 
-$U_{2,0} =$ <wrap onlyprint> \\ \\ </wrap> 
- 
-Calculate $U_{2{\rm L}}$ and $I_2$ for $R_{\rm L} = 10 ~{\rm k}\Omega$ using the values of the equivalent voltage source. State the formulae used. 
- 
-$U_{2{\rm L}}:$ <wrap onlyprint> \\ \\ \\ \\ </wrap> 
- 
-$I_2:$ <wrap onlyprint> \\ \\ \\ \\ </wrap> 
- 
-Verify the values by measurement: 
- 
-$U_{2{\rm L},meas}:$ <wrap onlyprint> \\ \\ </wrap> 
- 
-$I_{2,{\rm meas}}:$ <wrap onlyprint> \\ \\ </wrap> 
- 
-Verify the values using Kirchhoff's laws. State the formulae used. 
- 
-$U_{2{\rm L}}:$ <wrap onlyprint> \\ \\ \\ \\ </wrap> 
- 
-$I_2:$ <wrap onlyprint> \\ \\ \\ \\ </wrap> 
- 
-==== Non-linear resistors ==== 
- 
-All resistors investigated so far are linear resistors, for which the characteristic $I = f(U)$ is a straight line. See Figure 7. The resistance value of a linear resistor is independent of the current $I$ flowing through it or of the applied voltage $U$. 
- 
-{{drawio>lab_electrical_engineering:1_dc_circuit_theory:figure_7_linear_characteristic.svg}} 
- 
-For non-linear resistors there is no proportionality between current and voltage. The characteristic of such a resistor is shown in Figure 8. For these resistors one speaks of the static resistance $R$ and the dynamic (or differential) resistance $r$. 
- 
-The static resistance is determined for a particular operating point: at a given voltage, the current is read from the resistance characteristic. The calculation is carried out according to Ohm's law: 
- 
-\\ 
-$R = \frac{U}{I}$ 
-\\ 
- 
-The differential resistance around the operating point is calculated from the current difference caused by a change in the applied voltage: 
- 
-\\ 
-$r = \frac{\Delta U}{\Delta I}$ 
-\\ 
- 
-{{drawio>lab_electrical_engineering:1_dc_circuit_theory:figure_8_non_linear_characteristic.svg}} 
- 
-As an example of a non-linear resistor, an incandescent lamp is investigated. Build the measurement circuit shown in Figure 9. 
- 
-{{drawio>lab_electrical_engineering:1_dc_circuit_theory:figure_9_incandescent_lamp_measurement_circuit.svg}} 
- 
-Set the bench power supply to the voltage values from Table 7. Measure the corresponding current values and enter them in Table 7. 
- 
-^ $U / {\rm V}$ ^ 0.5 ^ 1.0 ^ 2.0 ^ 3.0 ^ 4.0 ^ 5.0 ^ 6.0 ^ 7.0 ^ 8.0 ^ 
-| $I / {\rm mA}$ |  |  |  |  |  |  |  |  |  | 
- 
-Plot the characteristic $I = f(U)$. 
-<wrap onlyprint> \\ \\ \\ \\ \\ \\ </wrap> 
- 
-Calculate the static resistance $R$ at the operating point $U = 7.0 ~{\rm V}$. 
-<wrap onlyprint> \\ \\ \\ \\ </wrap> 
- 
-Calculate the dynamic resistance $r$ at the operating point $U = 7.0 ~{\rm V}$. 
-<wrap onlyprint> \\ \\ \\ \\ </wrap> 
- 
-Compare the values with those from Section 1.2 (direct resistance measurement). 
-<wrap onlyprint> \\ \\ \\ \\ </wrap>