Unterschiede
Hier werden die Unterschiede zwischen zwei Versionen angezeigt.
Beide Seiten der vorigen Revision Vorhergehende Überarbeitung | |||
ee2:task_elndbo3xwi2klxuu_with_calculation [2024/07/03 13:05] mexleadmin angelegt |
ee2:task_elndbo3xwi2klxuu_with_calculation [2024/07/03 15:21] (aktuell) mexleadmin angelegt |
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- | b) The picture below shows the top view again. In which of the directions shown does the horizontal component of the resulting force act? | + | b) The picture below shows the top view again. In which of the directions shown does the horizontal component |
(Independent) | (Independent) | ||
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- | For the resulting current the direction of the path has to be considered with the right-hand rule: | + | |
- | | + | * The vertical component |
- | * $I_{(2)} = +I_3 + I_4 - I_1 \quad \rightarrow \quad \theta_{(2)} = 1 {~\rm A} + 4 {~\rm A} - 5 {~\rm A} $ | + | * It has to be perpendicular to $\vec{B}_{\rm v}$ and to $\vec{l}$. The right-hand rule has to be applied. |
- | * $I_{(3)} = +I_3 - I_4 - I_2 \quad \rightarrow \quad \theta_{(3)} = 1 {~\rm A} - 4 {~\rm A} - 2 {~\rm A} $ | + | |
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- | \begin{align*} | + | Only option $7.$ is perpendicular to $\vec{B}_{\rm v}$ and to $\vec{l}$ and points in the right direction by the right-hand rule. |
- | \theta_{(1)} &= -4 {~\rm A} \\ | + | |
- | \theta_{(2)} &= 0 {~\rm A} \\ | + | |
- | \theta_{(3)} & | + | |
- | \end{align*} | + | |
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