Unterschiede

Hier werden die Unterschiede zwischen zwei Versionen angezeigt.

Link zu dieser Vergleichsansicht

Beide Seiten der vorigen Revision Vorhergehende Überarbeitung
Nächste Überarbeitung		 Vorhergehende Überarbeitung
electrical_engineering_1:aufgabe_2.7.9 [2021/10/08 22:26] – [Bearbeiten - Panel] tfischerelectrical_engineering_1:aufgabe_2.7.9 [2023/03/19 19:03] (aktuell) – mexleadmin
Zeile 1: Zeile 1:
-<panel type="info" title="Exercise 2.7.9 - Variation: Simplifying Circuits II (written exam task, approx 8% of a 60 minute written exam, WS2020)"> <WRAP group><WRAP column 2%>{{fa>pencil?32}}</WRAP><WRAP column 92%>+<panel type="info" title="Exercise 2.7.9 - Variation: Simplifying Circuits II (written exam task, approx 8% of a 60-minute written exam, WS2020)"> <WRAP group><WRAP column 2%>{{fa>pencil?32}}</WRAP><WRAP column 92%>
  
 <WRAP right> <WRAP right>
Zeile 6: Zeile 6:
  
 Given is the adjoining circuit with \\ Given is the adjoining circuit with \\
-$R_1=10 \Omega$\\ +$R_1=10 ~\Omega$\\ 
-$R_2=20 \Omega$\\ +$R_2=20 ~\Omega$\\ 
-$R_3=5 \Omega$\\+$R_3=5 ~\Omega$\\
  
-1. determine the equivalent resistance $R_{eq}$ between A and B by summing the resistances.+1. Determine the equivalent resistance $R_{\rm eq}$ between A and B by summing the resistances.
  
 <button size="xs" type="link" collapse="Solution_2_7_9_1_Final_result">{{icon>eye}} Final result</button><collapse id="Solution_2_7_9_1_Final_result" collapsed="true"> <button size="xs" type="link" collapse="Solution_2_7_9_1_Final_result">{{icon>eye}} Final result</button><collapse id="Solution_2_7_9_1_Final_result" collapsed="true">
 \begin{align*} \begin{align*}
-R_{ges} &= \frac{20 \Omega \cdot 5 \Omega}{\frac{3}{2}\cdot 20 \Omega + 5 \Omega} = 2.858 \Omega \rightarrow 2.9 \Omega+R_{ges} &= \frac{20 ~\Omega \cdot 5 ~\Omega}{\frac{3}{2}\cdot 20 ~\Omega + 5 ~\Omega} = 2.858 ~\Omega \rightarrow 2.9 ~\Omega
 \end{align*} \end{align*}
  \\  \\
 </collapse> </collapse>
  
-2. now let the voltage from A to B be: $U_{AB}=U_0= 10 V$. What is the current $I$?+2. Now let the voltage from A to B be: $U_{\rm AB}=U_0= 10 ~\rm V$. What is the current $I$?
  
 <button size="xs" type="link" collapse="Solution_2_7_9_2_Final_result">{{icon>eye}} Final result</button><collapse id="Solution_2_7_9_2_Final_result" collapsed="true"> <button size="xs" type="link" collapse="Solution_2_7_9_2_Final_result">{{icon>eye}} Final result</button><collapse id="Solution_2_7_9_2_Final_result" collapsed="true">
 \begin{align*} \begin{align*}
-I =\frac{10V}{2 \cdot 5 \Omega} = 1 A+I =\frac{10~\rm V}{2 \cdot 5 ~\Omega} = 1 ~\rm A
 \end{align*} \end{align*}
  \\  \\