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electrical_engineering_1:network_analysis [2023/11/28 00:37]
mexleadmin 		electrical_engineering_1:network_analysis [2023/11/28 00:45] (aktuell)
mexleadmin
Zeile 536: Zeile 536:
 Based on the E24 series, the following values are next to the calculated ones: Based on the E24 series, the following values are next to the calculated ones:
 \begin{align*} \begin{align*}
-R_3 &= 43 {~\rm k\Omega}\\ +R_3^0 &= 43 {~\rm k\Omega}\\ 
-R_1 &= {{1}\over{3}}   (R_3 + 15 {~\rm k\Omega}) = 20 {~\rm k\Omega} \\ +R_1^0 &= {{1}\over{3}}   (R_3 + 15 {~\rm k\Omega}) = 20 {~\rm k\Omega} \\ 
-R_2 &= {{1}\over{5.09}}(R_3 + 15 {~\rm k\Omega}) = 12 {~\rm k\Omega} +R_2^0 &= {{1}\over{5.09}}(R_3 + 15 {~\rm k\Omega}) = 12 {~\rm k\Omega} 
 \end{align*} \end{align*}
  
 #@HiddenEnd_HTML~Result1,Result~@# #@HiddenEnd_HTML~Result1,Result~@#
  
-  * Find the relationship between $R_1$, $R_2$, and $R_3$ by investigating Kirchhoff's nodal rule for the node where $R_1$, $R_2$, and $R_3$ are interconnected.+2. Find the relationship between $R_1$, $R_2$, and $R_3$ by investigating Kirchhoff's nodal rule for the node where $R_1$, $R_2$, and $R_3$ are interconnected.
  
 #@HiddenBegin_HTML~Solution2,Solution~@# #@HiddenBegin_HTML~Solution2,Solution~@#
Zeile 579: Zeile 579:
 #@HiddenEnd_HTML~Solution2,Solution ~@# #@HiddenEnd_HTML~Solution2,Solution ~@#
  
-  * What is the input resistance $R_{\rm in}(R_1, R_2, R_3)$ of the circuit (viewed from the sensor)?+3. What is the input resistance $R_{\rm in}(R_1, R_2, R_3)$ of the circuit (viewed from the sensor)?
  
-#@HiddenBegin_HTML~~Solution3,~Solution~@#+#@HiddenBegin_HTML~Solution3,Solution~@#
  
 \begin{align*} \begin{align*}
Zeile 588: Zeile 588:
 \end{align*} \end{align*}
  
-#@HiddenEnd_HTML~~Solution3,~Solution~@#+#@HiddenEnd_HTML~Solution3,Solution~@#
  
-  * What is the minimum allowed input resistance ($R_{\rm in}(R_1, R_2, R_3)$) for the sensor to still deliver current?+4. What is the minimum allowed input resistance ($R_{\rm in, min}(R_1, R_2, R_3)$) for the sensor to still deliver current? 
 + 
 +#@HiddenBegin_HTML~Solution4,Solution~@# 
 + 
 +\begin{align*} 
 +R_{\rm in, min} &= {{U_{\rm sense}}\over{I_{\rm sense, max}}} \\ 
 +                &= \rm {{15 V}\over{1 mA}} \\ 
 +                &= 15 k\Omega \\ 
 +\end{align*} 
 + 
 +#@HiddenEnd_HTML~Solution4,Solution~@#
  
 #@TaskEnd_HTML@# #@TaskEnd_HTML@#