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lab05_en:inverting_op-amp_photo_diode_as_current_source [2026/04/02 12:58] – created mexleadminlab05_en:inverting_op-amp_photo_diode_as_current_source [2026/04/02 13:01] (current) – mexleadmin
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 === Photo Diode as current source === === Photo Diode as current source ===
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 +{{drawio>lab05:Fig-100_inverting_op-amp_photo_diode.svg}} 
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 +<imgcaption Fig-100_inverting_op-amp_photo_diode | Inverting Op-Amp: Photo Diode as current source> </imgcaption> 
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 +$U_{\rm DD}{\rm~=10~V},~U_{\rm SS}{\rm~=-10~V},~R_{\rm 1}{\rm~=10~k\Omega}$\\ \\ 
 +Use the values from <imgref Fig-20_inverting_op-amp> for $U_{\rm IN},~U_{\rm OUT},~R_{\rm 2}$. 
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 +Complete the arrows in the scematic of the circuit.\\ 
 +Take the values for $U_{\rm 1},~U_{\rm 2},~U_{\rm OUT}$ from <imgref Fig-30_inverting_op-amp_inv_input>.\\ 
 +Use these values to calculate the sum of the voltages at node ${\rm N_{12}}$.\\ 
 +Compare your result by measuerement. 
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 +$U_{\rm 1}{\rm~=}$ 
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 +$U_{\rm 2}{\rm~=}$ 
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 +$U_{\rm OUT}{\rm~=}$ 
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 +Calculated $U_{\rm 12}{\rm~=}$ 
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 +Measured $U_{\rm 12}{\rm~=}$ 
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 +What are your results?\\ 
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 +What will happen if you short-circuit $R_{\rm 2}$?\\ 
 +Try it and explain your results.\\ 
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