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--- mexlefirst_public:rectangular-to-triangle_signal_conversion_integrator [2026/08/05 10:08] – created feharst
+++ mexlefirst_public:rectangular-to-triangle_signal_conversion_integrator [2026/08/05 12:21] (current) – feharst
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+<wrap #rect-to-tri-conv-integrator>
 =====Rectangular-to-Triangle Signal Conversion - Integrator=====
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-<wrap left> {{drawio>mexlefirst_intern:integrator_circuit.svg}} </wrap>\\
+<wrap left> {{drawio>mexlefirst_public:integrator_circuit.svg}} </wrap>\\
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 Analysis of the circuit:\\
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-<wrap left> {{drawio>mexlefirst_intern:integrator_u-t-diagramme.svg}}\\
+<wrap left> {{drawio>mexlefirst_public:integrator_u-t-diagramme.svg}}\\
 </wrap>\\
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 ====Experimental Tasks====
+<wrap #tasks>
+<wrap #setup>
 To analyze the behavior of the integrator, the following circuit is used:\\
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-{{drawio>mexlefirst_intern:integrator_experiment.svg}}
+{{drawio>mexlefirst_public:integrator_experiment.svg}}
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-  - Calculate the time constant $T_\mathrm{i}$ of the integrator from the given values.
+</wrap>
-  - Assumption: the capacitor is initially uncharged. A voltage $u_\mathrm{e}=+3~V$ is applied to the input. How long does it take for the output voltage to reach $u_\mathrm{Tr}=-3~V$? Document your calculation.
-  - Roughly sketch the voltage curves that you expect at the TR output when you apply a bipolar square wave signal to the $u_\mathrm{e}$ input.\\ \\ **Output TR**\\ \\ <wrap left>{{drawio>mexlefirst_intern:oscilloscope_screen.svg}}</wrap>\\ \\ \\ Channel 1:$\frac {Volt}{Div}=$\\ \\ \\ Time basis: $\frac {T}{Div}=$\\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\
+  - [task-type-oscilloscope] Calculate the time constant $T_\mathrm{i}$ of the integrator from the given values.
-  - Build the circuit on the MEXLE-board. **Please use the level shifting circuit at the input of the circuit.** Make sure that the jumper at the bottom of the op-amp is set to the left so that the op-amp is supplied with +/- 3V. Connect channel 1 on the oscilloscope to $U_\mathrm{e}$ and channel 2 to TR. Connect the function generator to the $U_\mathrm{e}$ input. Set to square wave (bipolar) with a frequency of 3kHz and a voltage of 3 V (amplitude). Switch on the power supply. Take a photo of the oscilloscope screen image. \\ \\ \\ **C1 = 10 nF, f = 3 kHz**\\ \\ <wrap left>{{drawio>mexlefirst_intern:oscilloscope_screen.svg}}</wrap>\\ \\ \\ Channel 1: $\frac {Volt}{Div}=$\\ \\ Channel 2: $\frac {Volt}{Div}=$\\ \\ \\ Time basis: $\frac {T}{Div}=$\\ \\ \\ \\ \\ \\ \\ \\ \\
+  - [task-type-result] Assumption: the capacitor is initially uncharged. A voltage $u_\mathrm{e}=+3~V$ is applied to the input. How long does it take for the output voltage to reach $u_\mathrm{Tr}=-3~V$? Document your calculation.
-  - Compare your measurement with the calculation from part 2 and the forecast from part 3. Explain your result.
+  - [task-type-result] Roughly sketch the voltage curves that you expect at the TR output when you apply a bipolar square wave signal to the $u_\mathrm{e}$ input.\\ \\ **Output TR**\\ \\ <wrap left>{{drawio>mexlefirst_public:oscilloscope_screen.svg}}</wrap>\\ \\ \\ Channel 1:$\frac {Volt}{Div}=$\\ \\ \\ Time basis: $\frac {T}{Div}=$\\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\
+  - [task-type-oscilloscope] Build the circuit on the MEXLE-board. **Please use the level shifting circuit at the input of the circuit.** Make sure that the jumper at the bottom of the op-amp is set to the left so that the op-amp is supplied with +/- 3V. Connect channel 1 on the oscilloscope to $U_\mathrm{e}$ and channel 2 to TR. Connect the function generator to the $U_\mathrm{e}$ input. Set to square wave (bipolar) with a frequency of 3kHz and a voltage of 3 V (amplitude). Switch on the power supply. Take a photo of the oscilloscope screen image. \\ \\ \\ **C1 = 10 nF, f = 3 kHz**\\ \\ <wrap left>{{drawio>mexlefirst_public:oscilloscope_screen.svg}}</wrap>\\ \\ \\ Channel 1: $\frac {Volt}{Div}=$\\ \\ Channel 2: $\frac {Volt}{Div}=$\\ \\ \\ Time basis: $\frac {T}{Div}=$\\ \\ \\ \\ \\ \\ \\ \\ \\
+  - [task-type-freetext] Compare your measurement with the calculation from part 2 and the forecast from part 3. Explain your result.
+</wrap>
 ====Test Questions - Integrator====
+</wrap>