By the end of this section, you will be able to:
First, permanent magnets made of magnetic magnetite ($\rm Fe_{3} O_{4}$) were found in Greece in the region around Magnesia. Besides the iron materials, other elements also show a similar „strong and permanent magnetic force effect“, which is also called ferromagnetism after iron: Cobalt and nickel, as well as many of their alloys, also exhibit such an effect. Chapter 3.5 Matter in the magnetic field describes the subdivision of magnetic materials in detail.
Here now the „magnetic force effect“ is to be looked at more near. For this purpose, a few thought experiments are carried out with a magnetic iron stone Abbildung 21 (This video gives a similar introduction).
So it seems that there is a directed force around each of the two parts. If you dig a little deeper you will find that this force is focused on one part of the outer surface.
Of course, you already know magnets and also know that there are poles. The considered thought experiment shall clarify, how one could have proceeded at an unknown appearance. In further thought experiments, such magnet iron stones can also be cut into other directions and the forces analyzed.
The result here is:
Interestingly, even non-magnetized, ferromagnetic materials experience a force effect in the magnetic field. A non-magnetic nail is attracted by a permanent magnet. This even happens independently of the magnetic pole. This also explains the visualization about iron filings (= small ferromagnetic parts), see Abbildung 2. Also here there is a force effect and a torque, which aligns the iron filings. The visible field seems to form field lines here.
In 1820, Christian Ørsted discovered by chance during a lecture that current-carrying conductors also affect a compass. This experiment is illustrated in Abbildung 3. A long, straight conductor with a circular cross-section has current $I$ flowing through it. Due to symmetry considerations, the field line pattern must be radially symmetric concerning the conductor axis. In an experiment with a magnetic needle, it can be shown that the field lines form concentric circles.
Property | Electrostatic | Magnetostatic |
---|---|---|
Field line images | ||
sample for the field | positive sample charge | compass |
field lines | - start on a positive charge - end on a negative charge | - have no start and no end - are closed |
field line ends | there are sources and sinks | there are no sources and sinks |
field type | vortex-free source field | source-free vortex field |
By the end of this section, you will be able to:
Superposition of magnetic fields
Before the magnetic field strength will be considered in more detail, the simulation and superposition of the magnetic field will be discussed in more detail here.
Magnetostatic fields can be superposed, just like electrostatic fields. This allows the fields of several current-carrying lines to be combined into a single one. This trick is used in the following chapter to examine the magnetic field in more detail.
On the right side, the magnetic field of a single current-carrying conductor is shown. This was already derived in the previous chapter by symmetry considerations. The representation in the simulation can be simplified a bit here to see the conditions more clearly: Currently, the field lines are displayed in 3D, which is done by selecting Display: Field Lines
and No Slicing
. If you change the selection to Show Z Slice
instead of No Slicing
, you can switch to a 2D display. In this display, small compass needles can also show the magnetic field. To do this, select Display: Field Vectors
instead of Display: Field Lines
. In addition, a „magnetic sample“, i.e. a moving compass, can be found at the mouse pointer in the 2D display.
If there is another current-carrying conductor near the first conductor, the fields overlap. In the simulation below, the current of both conductors is directed in the same direction. The field between the conductors overlaps just enough to weaken. This can also be deduced by previous knowledge if just the middle point between both conductors is considered: There, for the left conductor the right-hand rule results in a vector directed towards the observer. For the right conductor, it results in a vector that is directed away from the observer. These just cancel each other out. Further outward field lines go around both conductors. The North and south poles here are not fixed localized toward the outside.
If, on the other hand, the current in the second conductor is directed in the opposite direction to the current in the first conductor, the picture changes: Here there is a reinforcing superposition between the two conductors. Using the nomenclature from the previous chapter, it is also possible to assign north and south poles locally. Towards the outside, one pole appears to be located in front of the two conductors and another one behind.
in both simulations, the distances between the conductors can also be changed using the Line Separation
slider. What do you notice in each case when the two lines are brought close together?
So far the magnetic field was defined quite pragmatically by the effect on a compass. For a deeper analysis of the magnetic field, the field is now to be considered again - as with the electric field - from two directions. The magnetic field will also be considered a „causer field“ (a field caused by magnets) and an „acting field“ (a field acting on a magnet). This chapter will first discuss the acting magnetic field. For this, it is convenient to consider the effects inside a toroidal coil (= donut-like setup). This can be seen in Abbildung 6. For reasons of symmetry, it is also clear here that the field lines form concentric circles.
In an experiment, a magnetic needle inside the toroidal coil is now to be aligned perpendicular to the field lines. Then, the magnetic field will generate a torque $M$ which tries to align the magnetic needle in the field direction.
It now follows:
To summarize: \begin{align*} M \sim {{I \cdot N}\over{l}} \end{align*}
The magnetic field strength $H$ inside the toroidal coil is given as: \begin{align*} \boxed{H ={{I \cdot N}\over{l}}} \quad \quad | \quad \text{applies to toroidal coil only} \end{align*}
For the unit of the magnetic field strength $H$ we get $[H] = {{[I]}\over{[l]}}= \rm 1~{{A}\over{m}}$
The previous derivation from the toroidal coil is now used to derive the field strength around a long, straight conductor. For a single conductor the part $N \cdot I$ of the formula can be reduced to $ N \cdot I = 1 \cdot I = I$ since there is only one conductor. For the toroidal coil, the magnetic field strength was given by this current(s) divided by the (average) field line length. Because of the (same rotational) symmetry, this is also true for the single conductor. Also here the field line length has to be taken into account.
The length of a field line around the conductor is given by the distance $r$ of the field line from the conductor: $l = l(r) = 2 \cdot \pi \cdot r$.
For the magnetic field strength of the single conductor we then get:
\begin{align*}
\boxed{H ={I\over{l}} = {{I}\over{2 \cdot \pi \cdot r}}} \quad \quad | \quad \text{applies only to the long, straight conductor}
\end{align*}
In the electric field, the field line density was a measure of the strength of the field. This is also used for the magnetic field. Looking at the simulations in Falstad (e.g. Abbildung 8) with this understanding, one notices an inconsistency: contrary to the relationship just given, the field line density in the Falstad simulation not indicates the strength of the field. A realistic simulation is shown in Abbildung 9 for comparison, which makes the difference clear: the field is stronger near the conductor. Thus the field line density must also be stronger there.
The cause of a magnetic field is a current. As seen for the coil, sometimes the current has to be counted up ($N \cdot I$), e.g. by the number of windings of the coil. If this current $I$ and/or the number $N$ of windings is increased, the effect is amplified. To make this easier to handle, we introduce the Magnetic Voltage. The magnetic voltage $\theta$ is defined as
\begin{align*} \boxed{\theta = \sum I = N \cdot I} \end{align*} The unit of $\theta$ is: $[\theta]= 1~ \rm A$ (obsoletely called ampere-turn). For the magnetic voltage the currents which flow through the surface enclosed by the closed path have to be considered. A detailed definition will be given below after more analysis.
Thus, the magnetic field strength $H$ of the toroidal coil is then given by: $H= {{\theta}\over{l}}$
In the English literature often the name Magnetomotive Force $\mathcal{F}$ is used instead of magnetic voltage $\theta$. The naming refers to the Electromotive Force. The electromotive force describes the root cause of a (voltage) source to be able to drive a current and therefore generate a defined voltage. Both „forces“ shall not be confused with the mechanical force $\vec{F}= m \cdot \vec{a}$. They only describe the driving cause behind the electric or magnetic fields. The German courses in higher semesters use the term Magnetische Spannung - therefore, the English equivalent is introduced here.
So far, only rotational symmetric problems could be solved. Now, this shall be generalized. For this purpose, we will have a look back at the electric field. For the electric field strength $E$ of a capacitor with two plates at a distance of $s$ and the potential difference $U$ holds:
\begin{align*} U = E \cdot s \quad \quad | \quad \text{applies to capacitor only} \end{align*}
In words: The potential difference is given by adding up the field strength along the path of a probe from one plate to the other. This was extended to $U = \int_s E {\rm d}s$. If we compare this idea to the magnetic field strength $H$ of a toroidal coil with the mean magnetic path length $l$, we had
\begin{align*} \theta = H \cdot l \quad \quad | \quad \text{applies to toroidal coil only} \end{align*}
Can you see the similarities? Again, the magnitude of the field strength is summed up along a path to arrive at another field-describing quantity (here, the magnetic voltage $\theta$). Because of the similarity - which continues below - the so-called magnetic potential difference $V_m$ is introduced:
\begin{align*} V_m = H \cdot s \quad \quad | \quad \text{applies to toroidal coil only} \end{align*}
Now, what is the difference between the magnetic potential difference $V_m$ and the magnetic voltage $\theta$?
Thus, for each infinitesimally small path ${\rm d}s$ along a field line, the resulting infinitesimally small magnetic potential difference ${\rm d}V_{\rm m} = H \cdot {\rm d}s$ can be determined. If now along the field line the magnetic field strength $H = H(\vec{s})$ changes, then the magnetic potential difference from point $\vec{s_1}$ to point $\vec{s_2}$ results to:
\begin{align*} V_{\rm m12} = V_{\rm m}(\vec{s_1}, \vec{s_2}) = \int_\vec{s_1}^\vec{s_2} H(\vec{s}) {\rm d}s \end{align*}
Up to now, only the situation was considered that one always walks along one single field line. $\vec{s}$ therefore always arrived at the same spot of the field line. If one wants to extend this to arbitrary directions (also perpendicular to field lines), then only that part of the magnetic field strength $\vec{H}$ may be used in the formula, which is parallel to the path ${\rm d} \vec{s}$. This is made possible by scalar multiplication. Thus, it is generally valid:
\begin{align*} \boxed{V_{\rm m12} = \int_\vec{s_1}^\vec{s_2} \vec{H} \cdot {\rm d} \vec{s}} \end{align*}
The magnetic voltage $\theta$ (and therefore the current) is the cause of the magnetic field strength. From the chapter The stationary Electric Flow the general representation of the current through a surface is known. This leads to the Ampere's Circuital Law
\begin{align*} \boxed{\oint_{s} \vec{H} \cdot {\rm d} \vec{s} = \iint_A \; \vec{S} {\rm d}\vec{A} = \theta} \end{align*}
Ampere's Circuital Law shall be applied to find the magnetic field strength $H$ inside the toroidal coil (Abbildung 13).
This leads to:
\begin{align*} \oint_s \vec{H} \cdot {\rm d} \vec{s} &= \iint_A \vec{S} {\rm d}\vec{A} = \theta \end{align*}
Since $\vec{H} \uparrow \uparrow {\rm d} \vec{s}$ the term $\vec{H} \cdot {\rm d} \vec{s}$ can be substituted by $H {\rm d}s$:
\begin{align*} \oint_s H \cdot {\rm d}s &= \iint_A \vec{S} {\rm d}\vec{A} \end{align*}
The magnetic voltage is the current through the surface and is given as $N\cdot I$:
\begin{align*} \oint_{\rm s} H \cdot {\rm d}s &= N\cdot I \end{align*}
The magnetic field strength $H$ can be considered constant:
\begin{align*} H \cdot \int_C {\rm d}s &= N\cdot I \end{align*}
The average coil circumference is $2\pi \cdot {{d}\over{2}}$:
\begin{align*} H \cdot 2\pi \cdot {{d}\over{2}} &= N\cdot I \end{align*}
Therefore, the magnetic field strength in the toroidal coil is \begin{align*} H &= {{N\cdot I}\over{ \pi \cdot d }} \end{align*}
Similarly, the magnetic field strength $H$ in the distance $r$ to a single conductor with the current $I$ can be derived. In this situation, the result is:
\begin{align*} H &= {{I}\over{ 2\pi \cdot r }} \end{align*}
By the end of this section, you will be able to:
In the last sub-chapter, the field effect on a magnet caused by currents was analyzed. Now, the field acting onto currents will get deeper investigation. To do so, the effect between two parallel conductors has to be examined closer. The experiment consists of a part $l$ of two very long1) conductors with the different currents $I_1, I_2$ in the distance $r$ (see Abbildung 14).
When no current is flowing through the conductors the forces er equal to zero. Once the currents flow in the same direction (e.g. $I_1>0, I_2>0$) attracting forces $\vec{F}_{12} = - \vec{F}_{21}$ appear. The force $\vec{F}_{xy}$ shall be the force on the conductor $x$ caused by conductor $y$. In the following the force $\vec{F}_{12}$ on the conductor $1$ will be examined.
The following is detectable:
To summarize: \begin{align*} {F}_{12} \sim {I_1 \cdot I_2 \cdot {{l}\over{r}}} \end{align*}
The proportionality factor is arbitrarily chosen as: \begin{align*} {{{F}_{12} \cdot r} \over {I_1 \cdot I_2 \cdot {l}}} = {{\mu}\over{2\pi}} \end{align*}
Here $\mu$ is the magnetic permeability and for vacuum (vacuum permeability): \begin{align*} \mu = \mu_0 = 4\pi \cdot 10^{-7} {{\rm Vs}\over{\rm Am}} = 1.257 \cdot 10^{-7} {{\rm Vs}\over{\rm Am}} \end{align*}
This leads to the Ampere's Force Law: \begin{align*} |\vec{F}_{12}| = {{\mu}\over{2 \pi}} \cdot {{I_1 \cdot I_2 }\over{r}} \cdot l \end{align*}
Since we want to investigate the effect on the current $I_1$, the following rearrangement can be done: \begin{align*} |\vec{F}_{12}| &= {{\mu}\over{2 \pi}} \cdot {{I_2 }\over{r}} &\cdot I_1 \cdot l \\ &= B &\cdot I_1 \cdot l \\ \end{align*}
The properties of the field from $I_2$ acting on $I_1$ are summarized to $B$ - the magnetic flux density.
$B$ has the unit:
\begin{align*}
[B] &= {{[F]}\over{[I]\cdot[l]}} = 1 \rm {{N}\over{Am}} = 1 {{{VAs}\over{m}}\over{Am}} = 1 {{Vs}\over{m^2}} \\
&= 1 {\rm T} \quad\quad({\rm Tesla})
\end{align*}
This formula can be generalized with the knowledge of the directions of the conducting wire $\vec{l}$, the magnetic field strength $\vec{B}$ and the force $\vec{F}$ using vector multiplication too:
\begin{align*} \boxed{\vec{F_L} = I \cdot \vec{l} \times \vec{B}} \end{align*}
The absolute value can be calculated by
\begin{align*} \boxed{|\vec{F_L}| = I \cdot |l| \cdot |B| \cdot \sin(\angle \vec{l},\vec{B} )} \end{align*}
The force is often called Lorentz Force $F_L$. For the orientation, another right-hand rule can be applied.
This is shown in Abbildung 14.
A way to remember the orientation is the mnemonic FBI (from middle finger to thumb):
The true Lorentz force is not the force on the whole conductor but the single force onto an (elementary) charge.
To find this force the previous force onto a conductor can be used as a start. However, the formula will be investigated infinitesimally for small parts ${\rm d} \vec{l}$ of the conductor:
\begin{align*} \vec{{\rm d}F}_{\rm L} = I \cdot {\rm d}\vec{l} \times \vec{B} \end{align*}
The current is now substituted by $I = {\rm d}Q/{\rm d}t$, where ${\rm d}Q$ is the small charge packet in the length $\vec{{\rm d}l}$ of the conductor.
\begin{align*} \vec{{\rm d}F}_{\rm L} = {{{\rm d}Q}\over{{\rm d}t}} \cdot {\rm d}\vec{l} \times \vec{B} \end{align*}
Mathematically not quite correct, but in a physical way true the following rearrangement can be done:
\begin{align*} \vec{{\rm d}F}_{\rm L} &= {{{\rm d}Q \cdot {\rm d}\vec{l}}\over{{\rm d}t}} \times \vec{B} \\ &= {\rm d}Q \cdot {{{\rm d}\vec{l}}\over{{\rm d}t}} \times \vec{B} \\ &= {\rm d}Q \cdot {{{\rm d}\vec{l}}\over{{\rm d}t}} \times \vec{B} \\ \end{align*}
Here, the part ${{{\rm d}\vec{l}}\over{{\rm d}t}}$ represents the speed $\vec{v}$ of the small charge packet ${\rm d}Q$.
\begin{align*} \vec{{\rm d}F}_{\rm L} &= {\rm d}Q \cdot \vec{v} \times \vec{B} \end{align*}
The Lorenz Force on a finite charge packet is the integration:
\begin{align*} \boxed{\vec{F}_{\rm L} = Q \cdot \vec{v} \times \vec{B}} \end{align*}
Please have a look at the German contents (text, videos, exercises) on the page of the KIT-Brückenkurs >> 5.2.3 Lorentz-Kraft. Make sure that Gesamt
is selected in the selection bar at the top. The last part „Magnetic field within matter“ can be skipped.
By the end of this section, you will be able to:
The magnetic interaction is also represented via two fields in the previous subchapters similar to the electric field.
Since the magnetic field strength $\vec{H}$ is only dependent on the field causing current $I$, this field is independent of surrounding matter.
The magnetic flux density $\vec{B}$ on the other hand, showed with the magnetic permeability a factor that can contain the material effects.
Both fields are connected. The Ampere's Force Law gave the formula
\begin{align*} |\vec{F}_{12}| &= {{\mu}\over{2 \pi}} \cdot {{I_2 }\over{r}} &\cdot I_1 \cdot l \\ &= B &\cdot I_1 \cdot l \\ \end{align*}
Therefore, the magnetic flux density $\vec{B}$ is equal to:
\begin{align*} B &= {{\mu}\over{2 \pi}} \cdot {{I_2 }\over{r}} \end{align*}
$I_2$ was here the field-causing current.
For the field strength of the straight conductor, we had:
\begin{align*} H &= {{I}\over{2 \pi \cdot r }} \end{align*}
The connection between the two fields is also $B = \mu \cdot H$. Since the field lines of both fields are always parallel to each other it results to
\begin{align*} \boxed{ \vec{B} = \mu \cdot \vec{H} } \end{align*}
This is similar to the $\vec{D} = \varepsilon \cdot \vec{E}$. Similarly, the permeability is separated into two parts:
\begin{align*} \mu &= \mu_0 \cdot \mu_{\rm r} \end{align*}
where
The material can be divided into different types by looking at its relative permeability. Abbildung 16 shows the relative permeability in the magnetization curve (also called $B$-$H$-curve). In this diagram, the different effect ($B$-field on $y$-axis) based on the causing external $H$-field (on $x$-axis) for different materials is shown. The three most important material types shall be discussed shortly.
A living insect („diamagnet“) floats in a very strong magnetic field
Explanation of diamagnetism and paramagnetism
Explanation of the hysteresis curve
The ferromagnetic materials can again be subdivided into two groups: magnetically soft and magnetically hard materials.
Applications:
Applications:
Wandering magnetic domains in a ferromagnetic material when the external field is reversed (from [email protected]).
The current $I_0 = 100~\rm A$ flows in a long straight conductor with a round cross-section. The conductor shall have constant electric properties everywhere. The radius of the conductor is $r_{\rm L}= 4~\rm mm$.
1. What is the magnetic field strength $H_1$ at a point $P_1$, which is outside the conductor at a distance of $r_1 = 10~\rm cm$ from the conductor axis?
The $H$-field is given as: \begin{align*} H(r) &= {{I_0}\over{2\pi \cdot r}} \\ &= {{100~\rm A}\over{2\pi \cdot 0.1 ~\rm m}} \\ \end{align*}
2. What is the magnetic field strength $H_2$ at a point $P_2$, which is inside the conductor at a distance of $r_2 = 3~\rm mm$ from the conductor axis?
The $H$-field is given as: \begin{align*} H(r) &= {{I}\over{2\pi \cdot r}} \end{align*}
But now $I$ is not $I_0$ anymore, but only a fraction, so $\Delta I$. $I_0$ is evenly distributed over the cross-section $A$ of the conductor. The cross-sectional area is given as $A= r^2 \cdot \pi$
So the current $\Delta I$ is given as: current divided by the full area and then times the fractional area: \begin{align*} \Delta I &= I_0 \cdot {{r_2^2 \cdot \pi}\over{r_{\rm L}^2 \cdot \pi}} \\ &= I_0 \cdot {{r_2^2 }\over{r_{\rm L}^2 }} \end{align*}
Therefore, the $H$-field is: \begin{align*} H(r) &= {{\Delta I}\over{2\pi \cdot r_2}} &&= {{I_0 \cdot {{ r_2^2}\over{r_{\rm L}^2}} }\over{2\pi \cdot r_2}} \\ &= {{I_0 \cdot {{ r_2}\over{r_{\rm L}^2}} }\over{2\pi}} &&= {{1}\over{2\pi}} I_0 \cdot {{ r_2}\over{r_{\rm L}^2}} \end{align*}
Three long straight conductors are arranged in a vacuum to lie at the vertices of an equilateral triangle (see Abbildung 21). The radius of the circumcircle is $r = 2 ~\rm cm$; the current is given by $I = 2 ~\rm A$.
1. What is the magnetic field strength $H({\rm P})$ at the center of the equilateral triangle?
In general, the $H$-field of the single conductor is given as: \begin{align*} H &= {{I}\over{2\pi \cdot r}} \\ &= {{2~\rm A}\over{2\pi \cdot 0.02 ~\rm m}} \\ \end{align*}
2. Now, the current in one of the conductors is reversed. To which value does the magnetic field strength $H({\rm P})$ change?
The $H$-field of the single reversed conductor $I_3$ is given as: \begin{align*} H(I_3) &= {{I}\over{2\pi \cdot r}} \\ &= {{2~\rm A}\over{2\pi \cdot 0.02 ~\rm m}} \\ \end{align*}
Once again, one can try to sketch the situation of the field vectors:
Therefore, it is visible, that the resulting field is twice the value of $H(I_3)$:
The vectors of $H(I_1)$ plus $H(I_2)$ had in the task 1 just the length of $H(I_3)$.
Given are the adjacent closed trajectories in the magnetic field of current-carrying conductors (see Abbildung 10). Let $I_1 = 2~\rm A$ and $I_2 = 4.5~\rm A$ be valid.
In each case, the magnetic voltage $V_{\rm m}$ along the drawn path is sought.
A $\rm NdFeB$ magnet can show a magnetic flux density up to $1.2 ~\rm T$ near the surface.
1. For comparison, the same flux density shall be created inside a toroidal coil with $10'000$ windings and a toroidal diameter for the average field line of $d = 1~\rm m$.
How much current $I$ is necessary for one of the windings of the toroidal coil?
The $B$-field is given as: \begin{align*} B &= \mu \cdot H \\ &= \mu \cdot {{I \cdot N}\over{l}} \\ \end{align*}
This can be rearranged to the current $I$: \begin{align*} I &= {{B \cdot l}\over{\mu \cdot N}} \\ &= {{1.2 ~\rm T \cdot 1 ~\rm m}\over{4\pi\cdot 10^-7 {\rm{Vs}\over{Am}} \cdot 10'000}} \end{align*}
2. What would be the current $I_{\rm Fe}$, when a iron core with $\varepsilon_{\rm Fe,r} = 10'000$?
Now $\mu$ has to be given as $\mu_r \cdot \mu_0$:
This can be rearranged to the current $I$: \begin{align*} I &= {{B \cdot l}\over{\mu \cdot N}} \\ &= {{1.2 ~\rm T \cdot 1 ~\rm m}\over{10'000 \cdot 4\pi\cdot 10^-7 {\rm{Vs}\over{Am}} \cdot 10'000}} \end{align*}
An electron shall move with the velocity $\vec{v}$ in a plate capacitor parallel to the plates, which have a potential difference $U$ and a distance $d$. In the vacuum in between the plates acts additionally a magnetic field $\vec{B}$.
Calculate the velocity depending on the other parameters $\vec{v} = f(U, |\vec{B}|, d) $!
\begin{align*} \vec{F}_C = q_e \cdot \vec{E} \end{align*}
Within the magnetic field, also the Lorentz force acts on the electron:
\begin{align*} \vec{F}_L = q_e \cdot \vec{v} \times \vec{B} \end{align*}
The absolute value of both forces must be equal to compensate each other:
\begin{align*} |\vec{F}_C| &= |\vec{F}_L|\\ |q_e \cdot \vec{E}| &= |q_e \cdot \vec{v} \times \vec{B}| \\ q_e \cdot |\vec{E}| &= q_e \cdot |\vec{v} \times \vec{B}| \\ |\vec{E}| &= |\vec{v} \times \vec{B}| \\ \end{align*}
Since $\vec{v}$ is perpendicular to $\vec{B}$ the right side is equal to $|\vec{v}| \cdot |\vec{B}| = v \cdot B$.
Additionally, for the plate capacitor $|\vec{E}|= U/d$.
Therefore, it leads to the following:
\begin{align*} {{U}\over{d}} &= v \cdot B \\ v &= {{U}\over{B \cdot d}} \end{align*}
Task 1