Unterschiede

Hier werden die Unterschiede zwischen zwei Versionen angezeigt.

Link zu dieser Vergleichsansicht

Beide Seiten der vorigen Revision Vorhergehende Überarbeitung
Nächste Überarbeitung		 Vorhergehende Überarbeitung
circuit_design:uebungsblatt6 [2021/11/16 22:03] – [Bearbeiten - Panel] slinncircuit_design:uebungsblatt6 [2023/12/16 01:13] (aktuell) – [Bearbeiten - Panel] mexleadmin
Zeile 16: Zeile 16:
  
 In the following, the transfer function of the differential amplifier is to be calculated. To do this, you should follow a few steps. In the following, the transfer function of the differential amplifier is to be calculated. To do this, you should follow a few steps.
-  - Derive the function $U_A = f(U_{E1}, U_{E2})$ using superposition. +  - Derive the function $U_{\rm O} = f(U_{\rm I1}, U_{\rm I2})$ using superposition. 
     - To do this, first draw an equivalent circuit in each case.      - To do this, first draw an equivalent circuit in each case. 
     - Briefly describe the resulting circuit. Which amplification circuit results in each case?     - Briefly describe the resulting circuit. Which amplification circuit results in each case?
-    - Then calculate the voltages $U_A1$ and $U_A2$, and from them $U_A$. +    - Then calculate the voltages $U_{\rm O1}$ and $U_{\rm O2}$, and from them $U_\rm O$. 
-  - Determine the function $U_A = f(U_{E1}, U_{E2})$ or the resistance values ​​of the circuit shown.+  - Determine the function $U_{\rm O} = f(U_{\rm I1}, U_{\rm I2})$ or the resistance values ​​of the circuit shown.
  
 </WRAP></WRAP></panel> </WRAP></WRAP></panel>
Zeile 29: Zeile 29:
 Derive the gain for the current-voltage converter, i.e. the transmission resistance. Use the procedure that we used for the other amplifiers. Derive the gain for the current-voltage converter, i.e. the transmission resistance. Use the procedure that we used for the other amplifiers.
  
-  - Draw a circuit with the relevant voltages, currents, resistances and the amplifiers+  - Draw a circuit with the relevant voltages, currents, resistances, and the operational amplifier
   - What are you looking for?   - What are you looking for?
-  - Number of variables +  - What is the number of variables 
-  - Number of equations required?+  - What is the number of equations required?
   - Establishing the known equations.   - Establishing the known equations.
   - Derivation of the transmission resistance.    - Derivation of the transmission resistance. 
Zeile 38: Zeile 38:
  
 <WRAP pagebreak></WRAP> <WRAP pagebreak></WRAP>
-<panel type="info" title="Exercise 4.5.1 Transfer steepness of the voltage-current transformer"> <WRAP group><WRAP column 2%>{{fa>pencil?32}}</WRAP><WRAP column 92%>+<panel type="info" title="Exercise 4.5.1 Transfer Conductance of the voltage-current converter"> <WRAP group><WRAP column 2%>{{fa>pencil?32}}</WRAP><WRAP column 92%>
  
-Here, too, derive the gain for the voltage-to-current transformer, i.e. the rate of transfer. Use the same procedure that we used for the other amplifiers.+Derive the "amplification" for the voltage-to-current converter, i.e. the transfer conductance. Use the same procedure that we used for the other amplifiers.
  
-  - Draw a circuit with the relevant voltages, currents, resistances and the amplifier.+  - Draw a circuit with the relevant voltages, currents, resistances, and the operational amplifier.
   - What are you looking for?   - What are you looking for?
-  - number of variables? +  - What is the number of variables? 
-  - number of necessary equations?+  - What is the number of necessary equations?
   - Establishing the known equations.   - Establishing the known equations.
-  - Derivation of the transmission slope. +  - Derivation of the transfer conductance. 
 </WRAP></WRAP></panel> </WRAP></WRAP></panel>
  
Zeile 55: Zeile 55:
 {{ elektronische_schaltungstechnik:erdbezogenelast.jpg?200|}} {{ elektronische_schaltungstechnik:erdbezogenelast.jpg?200|}}
  
-If the voltage-current converter is used as a current source, it must be ensured that the load has no contact with ground..+If the voltage-current converter is used as a current source, it must be ensured that the load has no contact with the ground.
  
-  - Draw the voltage-to-current transformer with a load that is in contact with ground. +  - Draw the voltage-to-current transformer with a load that is in contact with the ground. 
-  - In this case, why is the transmission slope derived above no longer valid as a gain factor?+  - Why is in this case the slope derived above no longer valid as an amplification factor?
   - Will the output current be higher or lower in this case?   - Will the output current be higher or lower in this case?
  
 </WRAP></WRAP></panel> </WRAP></WRAP></panel>
  
-<WRAP pagebreak></WRAP> 
-<panel type="info" title="Exercise 4.6 Meta-question"> <WRAP group><WRAP column 2%>{{fa>pencil?32}}</WRAP><WRAP column 92%> 
- 
-To prepare for the exam, you should also deal with the material and possible questions about it. To do this, develop **two individual questions** on the previous material, which 
-  * either concern a partial aspect that you do not yet understand, or 
-  * concern a partial aspect that you have learned in the last lesson. 
-Note that the questions should be asked in terms of difficulty so that they can also be found in the exam. Words that are too general ("Explain an operational amplifier") should be avoided. 
-\\I will play back the submitted questions to you via ILIAS and incorporate them into the exam. 
-\\ 
-\\ 
-In addition to this task, you are also welcome to write to me other content-related questions to which you would like an answer. 
-  
-However, you should mark these separately. 
-</WRAP></WRAP></panel>