Inverting Operational Amplifier

Gain of Op-Amp

Build the following circuit in figure 1 with the power supply and a multimeter.

Fig. 1: Inverting Op-Amp

$U_{\rm DD}{\rm~=10~V},~U_{\rm SS}{\rm~=-10~V},~R_{\rm 1}{\rm~=10~k\Omega}$

Calculate the necessary value for $R_{\rm 2}$, so that the Output $U_{\rm OUT}$ is +5 V. Use the supply voltage of the operational amplifier for $U_{\rm IN}$.


$U_{\rm IN}{\rm~=}$



















$R_{\rm 2}{\rm~=}$

Investigation of inverting input

Fig. 2: Inverting Op-Amp: Investigate currents of the inverting input

$U_{\rm DD}{\rm~=10~V},~U_{\rm SS}{\rm~=-10~V},~R_{\rm 1}{\rm~=10~k\Omega}$

Use the values from figure 1 for $U_{\rm IN},~U_{\rm OUT},~R_{\rm 2}$.


Complete the arrows in the scematic of the circuit.
Determine the the currents $I_{\rm 1}$ and $I_{\rm 2}$ indirectly by measuring the voltage.
Calculate the sum of the currents at node ${\rm N_{12}}$.


$U_{\rm 1}{\rm~=}$


$U_{\rm 2}{\rm~=}$







































$I_{\rm 1}{\rm~=}$


$I_{\rm 2}{\rm~=}$


$I_{\rm N12}{\rm~=}$




Fig. 3: Inverting Op-Amp: Investigate the virtual GND of the inverting input

$U_{\rm DD}{\rm~=10~V},~U_{\rm SS}{\rm~=-10~V},~R_{\rm 1}{\rm~=10~k\Omega}$

Use the values from figure 1 for $U_{\rm IN},~U_{\rm OUT},~R_{\rm 2}$.


Complete the arrows in the scematic of the circuit.
Take the values for $U_{\rm 1},~U_{\rm 2},~U_{\rm OUT}$ from figure 2.
Use these values to calculate the sum of the voltages at node ${\rm N_{12}}$.
Compare your result by measuerement.


$U_{\rm 1}{\rm~=}$


$U_{\rm 2}{\rm~=}$


$U_{\rm OUT}{\rm~=}$


Calculated $U_{\rm 12}{\rm~=}$


Measured $U_{\rm 12}{\rm~=}$


What are your results?

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What will happen if you short-circuit $R_{\rm 2}$?
Try it and explain your results.


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