Series Circuit of a Resistor and an Inductor

Background information

The apparent resistance of an inductor is frequency-dependent. The inductive reactance is given by: $$X_{\rm L} = \omega \cdot L$$
For a resistor and an inductor connected in series, the impedance magnitude is calculated as:
$$Z = \sqrt{R_{\rm 1}^2 + (ωL_{\rm 1})^2}$$

Experimental Tasks

1. Assemble the measurement circuit shown in figure 1:
   

   Fig. 1: Series Circuit of a Resistor and an inductor

   
   The corresponding phasor diagram is also illustrated in figure 1.
   

2. Set the function generator to produce a sinusoidal voltage with a frequency of 6 kHz and an amplitude of 6 V.
3. Measure the amplitude and frequency using the oscilloscope.
   
   
4. Sketch the time-domain waveforms of the voltages $u_{\rm F}$ and $u_{\rm L}$, clearly indicating the phase shift between them.
   
   Fig. 2 Channel 1: $ \frac{V}{\rm DIV} = $
   
   Channel 2: $ \frac{V}{\rm DIV} = $
   
   
   Time basis: $ \frac{T}{\rm DIV} = $
   

1. Draw the phasor diagram using the measured values.
2. Calculate the impedance $Z$, the current amplitude $\hat{I}$, and the voltage amplitudes $\hat{U}_{\rm R}$ and $\hat{U}_{\rm L}$ from the known component values $R_{\rm 1}$, $L_{\rm 1}$ and the source voltage amplitude $\hat{U}_{\rm F}$.
3. Compare the calculated results with the measured values.
   
   
   
   
   
   
4. Repeat this using an inductor with an inductance of 10 mH
   
   Fig. 3 Channel 1: $ \frac{V}{\rm DIV} = $
   
   Channel 2: $ \frac{V}{\rm DIV} = $
   
   Time basis: $ \frac{T}{\rm DIV} = $
   

1. Draw the corresponding phasor diagram based on the measured data.

Test questions - Series Circuit of a Resistor and an Inductor